所以我用C编码，我需要提出一些代码，该代码将从用户那里获取n个数字，并找到它们的最小值，最大值，平均值和平方和。到目前为止，我有平均值和平方和部分，但最小值和最大值是咬我的。
请记住，我处于一个非常基本的水平，我还没有到达阵列。我所知道的只是逻辑运算符，函数，循环以及stdlib.h，math.h和stdio.h库的使用。
这是我到目前为止所拥有的。 当我在编译期间尝试将float和double放在一起时，平均函数给了我很多问题，因此将它乘以1.0固定。我拥有一切，只有最小和最大。我一直把最后一个条目作为我的最大值，并将0作为我的最小值。
#include<stdio.h>
int main()
{
float average;
int i, n, count=0, sum=0, squaresum=0, num, min, max;
printf("Please enter the number of numbers you wish to evaluate\n");
scanf_s("%d",&n);
printf("Please enter %d numbers\n",n);
while(count<n)
{
min=0;
max=0;
if(num>max)
max=num;
if(num<min)
min=num;
scanf_s("%d",&num);
sum = sum+num;
squaresum = squaresum + (num*num);
count++;
}
average = 1.0*sum/n;
printf("Your average is %.2f\n",average);
printf("The sum of your squares is %d\n",squaresum);
printf("Your maximum number is %d\n",max);
printf("Your minimum number is %d\n",min);
return(0);
}
答案 0 :(得分：3)
你的算法不太对劲。以下是正确的实施：
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int main(void)
{
float average;
int n, num, count = 0, sum = 0, squaresum = 0;
int min = INT_MAX, max = INT_MIN;
bool gotAnswer = false;
/* Don't Let User Enter Wrong Input */
while(!gotAnswer)
{
printf("Please enter the number of numbers you wish to evaluate: ");
if(scanf_s("%d", &n) != 1)
{
/* User Entered Wrong Input; Clean Up stdin Stream*/
while(getchar() != '\n')
{
continue;
}
}
else
{
/* User Input Was Good */
gotAnswer = true;
}
}
/* Clear stdin Stream Just In Case */
while(getchar() != '\n')
continue;
while(count < n)
{
/* Don't Let User Enter Wrong Input */
gotAnswer = false;
printf("Enter number %d: ", count + 1);
if(scanf_s("%d", &num) != 1)
{
/* User Entered Wrong Input; Clean Up stdin Stream */
while(getchar() != '\n')
continue;
/* Let User Try Again */
continue;
}
else
{
/* User Input Was Correct */
gotAnswer = true;
/* Clear stdin Stream Just In Case */
while(getchar() != '\n')
continue;
}
if(num > max)
max = num;
if(num < min)
min = num;
sum += num;
squaresum += num * num;
count++;
}
average = 1.0 * sum / n;
printf("Your average is %.2f\n", average);
printf("The sum of your squares is %d\n", squaresum);
printf("Your maximum number is %d\n", max);
printf("Your minimum number is %d\n", min);
system("pause");
return 0;
}
我添加了错误检查和恢复。如果您对逻辑有任何疑问，请询问。
答案 1 :(得分：2)
当前编写代码的方式，min必须以较高的值（不是0）开始，否则代码将无效。要选择的最佳值是int的最大可能值。
您还应该考虑是否要在每次循环时重置这些变量。
答案 2 :(得分：1)
在循环外输入第一个num并将其分配给max min
scanf("%d",&num);
max = min = num;
将while循环更改为无限循环
while(1) {...}
现在检查您的计数器count是否等于n是否与break无限循环
if(count == n)
break;
修改后的完整代码：
#include<stdio.h>
int main()
{
float average;
int i, n, count=0, sum=0, squaresum=0, num, min, max;
printf("Please enter the number of numbers you wish to evaluate\n");
scanf_s("%d",&n);
printf("Please enter %d numbers\n",n);
scanf_s("%d",&num);
max = min = num;
while(1)
{
if(num>max)
max=num;
if(num<min)
min=num;
sum = sum+num;
squaresum = squaresum + (num*num);
count++;
if(count == n)
break;
scanf_s("%d",&num);
}
average = 1.0*sum/n;
printf("Your average is %.2f\n",average);
printf("The sum of your squares is %d\n",squaresum);
printf("Your maximum number is %d\n",max);
printf("Your minimum number is %d\n",min);
return(0);
}
答案 3 :(得分：1)
假设列表中的第一个数字为最小值和最大值。 将每个下一个字符与当前最小值和当前最大值进行比较，并相应地更新。
答案 4 :(得分：0)
你的while循环应该看起来像
min=3;
max=0;
while(count<n)
{
scanf("%d",&num);
if(num>max)
max=num;
if(num<min)
min=num;
sum = sum+num;
squaresum = squaresum + (num*num);
count++;
}
我同意 Robert Harvey♦ .. 您必须设置min
答案 5 :(得分：0)
您的代码中存在一些问题：
num ？您应该在 min和max num分配给max和{{1} }。 类似的东西：
min答案 6 :(得分：0)
添加布尔值，移动给出值min，max 0是循环的开始
#include<stdio.h>
int main()
{
float average;
int i, n, count=0, sum=0, squaresum=0, num, min, max;
bool first = true;
printf("Please enter the number of numbers you wish to evaluate\n");
scanf_s("%d",&n);
printf("Please enter %d numbers\n",n);
min=0;
max=0;
while(count<n)
{
scanf_s("%d",&num);
if (first) {
first = false;
min = max = num;
}
if(num>max)
max=num;
if(num<min)
min=num;
sum = sum+num;
squaresum = squaresum + (num*num);
count++;
}
average = 1.0*sum/n;
printf("Your average is %.2f\n",average);
printf("The sum of your squares is %d\n",squaresum);
printf("Your maximum number is %d\n",max);
printf("Your minimum number is %d\n",min);
return(0);
}
还应该考虑检查scanf的返回值
答案 7 :(得分：0)
npm run wbp
ERROR in ./node_modules/css-loader/dist/cjs.js?{"modules":false,"importLoaders":2,"sourceMap":true,"minimize":true}!./node_modules/react-base-table/styles.css
Module build failed: ValidationError: Invalid options object. CSS Loader has been initialised using an options object that does not match the API schema.
- options has an unknown property 'minimize'. These properties are valid:
object { url?, import?, modules?, sourceMap?, importLoaders?, localsConvention?, onlyLocals?, esModule? }
at validate (/Users/ivanfigueredo/Documents/Projects/OptionsAPI/node_modules/schema-utils/dist/validate.js:85:11)
at Object.loader (/Users/ivanfigueredo/Documents/Projects/OptionsAPI/node_modules/css-loader/dist/index.js:34:28)
@ ./node_modules/react-base-table/styles.css 2:26-87
@ ./wwwroot/source/optionsList.jsx
@ ./wwwroot/source/app.js