通过ajax将数据插入mysql数据库

时间：2013-12-25 05:31:25

标签： php ajax

通讯：

<form id="form-search" method="post" action="<?php echo $_SERVER['PHP_SELF'];?>">
    <span><span class="style2">Enter you email here</span>:</span>
    <input name="email" type="email" id="email" required/>

 <input type="submit" value="subscribe" class="submit" onclick="return fun()" />
                        </form>
                        <?php
mysql_connect("localhost","","");
mysql_select_db("");
error_reporting(E_ALL && ~E_NOTICE);

$email=$_POST['email'];
$sql="INSERT INTO newsletter_email(email) VALUES ('$email')";
$result=mysql_query($sql);
if($result){
echo "You have been successfully subscribed.";
}
 if(!$sql)
die(mysql_error());

mysql_close();

?>

但我想通过Ajax将我的电子邮件插入数据库。我不希望我的页面被重定向，因为每次刷新页面时，都会将空值插入数据库..

我只是希望我的电子邮件通过Ajax插入数据库，然后是电子邮箱 即。

<input name="email" type="email" id="email" required/>  
<input type="submit" value="subscribe" class="submit" onclick="return fun()" />

应该消失，并且应该有“你已经成功订阅”的行......

任何简短的代码都非常有用..提前谢谢你：）

6 个答案:

答案 0 :(得分：11)

试试这个：

  $(document).on('click','#save',function(e) {
  var data = $("#form-search").serialize();
  $.ajax({
         data: data,
         type: "post",
         url: "insertmail.php",
         success: function(data){
              alert("Data Save: " + data);
         }
});
 });

并在insertmail.php: 

<?php 
if(isset($_REQUEST))
{
        mysql_connect("localhost","root","");
mysql_select_db("eciticket_db");
error_reporting(E_ALL && ~E_NOTICE);

$email=$_POST['email'];
$sql="INSERT INTO newsletter_email(email) VALUES ('$email')";
$result=mysql_query($sql);
if($result){
echo "You have been successfully subscribed.";
}
}
?>

请勿使用mysql_弃用。

another method:

实际上如果你的问题是空值插入数据库然后试试这里，这里不需要ajax。 

<?php
if($_POST['email']!="")
{
    mysql_connect("localhost","root","");
    mysql_select_db("eciticket_db");
    error_reporting(E_ALL && ~E_NOTICE);
    $email=$_POST['email'];
    $sql="INSERT INTO newsletter_email(email) VALUES ('$email')";
    $result=mysql_query($sql);
    if($result){
    //echo "You have been successfully subscribed.";
              setcookie("msg","You have been successfully subscribed.",time()+5,"/");
              header("location:yourphppage.php");
    }
     if(!$sql)
    die(mysql_error());
    mysql_close();
}
?>
    <?php if(isset($_COOKIE['msg'])){?>
       <span><?php echo $_COOKIE['msg'];setcookie("msg","",time()-5,"/");?></span> 
    <?php }?>
<form id="form-search" method="post" action="<?php echo $_SERVER['PHP_SELF'];?>">
    <span><span class="style2">Enter you email here</span>:</span>
    <input name="email" type="email" id="email" required/>
    <input type="submit" value="subscribe" class="submit"/>
</form>

答案 1 :(得分：3)

ajax将成为一个javascript片段，它将信息传递给一个可以满足您需求的小型php文件。所以在你的页面中，而不是所有的PHP，你想要一个小javascript，更喜欢jquery：

function fun()
{
    $.get('\addEmail.php', {email : $(this).val()}, function(data) {
        //here you would write the "you ve been successfully subscribed" div
    });
}

你输入也必须是：

<input type="button" value="subscribe" class="submit" onclick="fun();" />

最后文件addEmail.php应该类似于：

mysql_connect("localhost","root","");
mysql_select_db("eciticket_db");

error_reporting(E_ALL && ~E_NOTICE);

$email=mysql_real_escape_string($_GET['email']);
$sql="INSERT INTO newsletter_email(email) VALUES ('$email')";
$result=mysql_query($sql);
if($result){
echo "You have been successfully subscribed.";
}
 if(!$sql)
die(mysql_error());

mysql_close();

同样sergey是对的，你应该使用mysqli。这不是一切，但足以让你开始。

答案 2 :(得分：2)

为什么要使用普通的jquery ajax功能。为什么不使用jquery ajax表单插件，它将表单数据通过ajax发布到表单操作链接。

在此处查看：

http://malsup.com/jquery/form/#getting-started

它非常易于使用和支持多种数据格式，包括json，html xml等。查看示例，您会发现它非常易于使用。

谢谢

答案 3 :(得分：0)

可用的答案导致我在数据库中输入空值。我通过使用以下代码替换serialize（）函数来更正此错误。

$(document).ready(function(){

// When click the button.
$("#button").click(function() {

    // Assigning Variables to Form Fields
    var email = $("#email").val();

    // Send the form data using the ajax method
    $.ajax({
        data: "email=" + email,
        type: "post",
        url: "your_file.php",
        success: function(data){
            alert("Data Save: " + data);
        }
    });

});

});

答案 4 :(得分：0)

我将告诉您如何使用PHP

在ajax中插入数据的步骤

AJAX代码

<script type="text/javascript">
function insertData() {
var student_name=$("#student_name").val();
var student_roll_no=$("#student_roll_no").val();
var student_class=$("#student_class").val();


// AJAX code to send data to php file.
    $.ajax({
        type: "POST",
        url: "insert-data.php",
        data: {student_name:student_name,student_roll_no:student_roll_no,student_class:s
         tudent_class},
        dataType: "JSON",
        success: function(data) {
         $("#message").html(data);
        $("p").addClass("alert alert-success");
        },
        error: function(err) {
        alert(err);
        }
    });

 }

</script>

PHP代码： 

<?php

include('db.php');
$student_name=$_POST['student_name'];
$student_roll_no=$_POST['student_roll_no'];
$student_class=$_POST['student_class'];

$stmt = $DBcon->prepare("INSERT INTO 
student(student_name,student_roll_no,student_class) 
VALUES(:student_name, :student_roll_no,:student_class)");

 $stmt->bindparam(':student_name', $student_name);
 $stmt->bindparam(':student_roll_no', $student_roll_no);
 $stmt->bindparam(':student_class', $student_class);
 if($stmt->execute())
 {
  $res="Data Inserted Successfully:";
  echo json_encode($res);
  }
  else {
  $error="Not Inserted,Some Probelm occur.";
  echo json_encode($error);
  }



  ?>

您可以根据需要自定义。您还可以查看AJAX Insert Data PHP

的完整步骤

答案 5 :(得分：-1)

AJAX：

$(document).on('click','#mv_secure_page',function(e) {
    var data = $("#m_form1").serialize();
    $.ajax({
        data: data,
        type: "post",
        url: "adapter.php",
        success: function(data){
        alert("Data: " + data);
        }
    });
});

php代码：

<?php
/**
 * Created by PhpStorm.
 * User: Engg Amjad
 * Date: 11/9/16
 * Time: 1:28 PM
 */


if(isset($_REQUEST)){
    include_once('inc/system.php');

    $full_name=$_POST['full_name'];
    $business_name=$_POST['business_name'];
    $email=$_POST['email'];
    $phone=$_POST['phone'];
    $message=$_POST['message'];

    $sql="INSERT INTO mars (f_n,b_n,em,p_n,msg) values('$full_name','$business_name','$email','$phone','$message') ";

    $sql_result=mysqli_query($con,$sql);
    if($sql_result){
       echo "inserted successfully";
    }else{
        echo "Query failed".mysqli_error($con);
    }
}
?>
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