Question

我有一个sql表，其中对于某列中某个值的每个更改都说C列，我想在其下插入一个新行来创建一个新事务。我不确定如何找到值更改并插入新行。我一直在通过csv文件上的VB代码执行此操作我导入到表中但无法在SQL中编写它。

Sub InsertRows()
  Dim r As Long, mcol As String, i As Long

' find last used cell in Column A
  r = Cells(Rows.Count, "A").End(xlUp).Row

 ' get value of  last used cell in column A
  mcol = Cells(r, 1).Value

 ' insert rows by looping from bottom
  For i = r To 2 Step -1
     If Cells(i, 1).Value <> mcol Then
       mcol = Cells(i, 1).Value
        Rows(i + 1).Insert
     End If
  Next i

End Sub

以下是示例数据

ID  JOB FNAME   LNAME   ADDRESS1    ADDRESS2    DATE    Concatenated
1234    A   John    Smith   4378 Anna St    Seattle-WA-98040    12/24/2013  1234-A-41632
1234    A   John    Doe 3564 Lucie Ave  Mercer Island-WA-98040  12/24/2013  1234-A-41632
1235    A   Alex    Smith   4554 Devon Ave  Chicago-IL-60563    12/24/2013  1235-A-41632
1235    A   Eli Manning 5555 Stranz Lane    Dallas-TX-75213 12/24/2013  1235-A-41632
1233    B   John    Smith   4378 Anna St    Seattle-WA-98040    12/24/2013  1233-B-41632
1233    C   John    Doe 3564 Lucie Ave  Mercer Island-WA-98040  12/24/2013  1233-C-41632
1236    D   Alex    Smith   4554 Devon Ave  Chicago-IL-60563    12/24/2013  1236-D-41632
1236    E   Eli Manning 5555 Stranz Lane    Dallas-TX-75213 12/24/2013  1236-E-41632

以下是所需的输出

ID  JOB FNAME   LNAME   ADDRESS1    ADDRESS2    DATE    Concatenated
1234    A   John    Smith   4378 Anna St    Seattle-WA-98040    12/24/2013  1234-A-41632
1234    A   John    Doe 3564 Lucie Ave  Mercer Island-WA-98040  12/24/2013  1234-A-41632

1235    A   Alex    Smith   4554 Devon Ave  Chicago-IL-60563    12/24/2013  1235-A-41632
1235    A   Eli Manning 5555 Stranz Lane    Dallas-TX-75213 12/24/2013  1235-A-41632

1233    B   John    Smith   4378 Anna St    Seattle-WA-98040    12/24/2013  1233-B-41632

1237    C   John    Doe 3564 Lucie Ave  Mercer Island-WA-98040  12/24/2013  1237-C-41632

1236    D   Alex    Smith   4554 Devon Ave  Chicago-IL-60563    12/24/2013  1236-D-41632

1236    E   Eli Manning 5555 Stranz Lane    Dallas-TX-75213 12/24/2013  1236-E-41632

“concatenated”列是我试图找到更改并在每次更改后插入一行的地方。任何帮助将不胜感激。

Answer 1

你真的想要编写一个存储过程，从你的数据源运行到你的数据库或者你的数据库中依赖的时间。

这是代码

BEGIN;

ALTER TABLE Test_table ADD COLUMN b1（10,2）;

UPDATE test_table SET romney_pct = CAST（romney as DECIMAL（10,2））/ CAST（uspres_total AS DECIMAL（10,2）;

COMMIT;

为列中的每个值更改插入一个新行

1 个答案: