Question

您好我在asp.net WebApi中创建了一个异常处理机制，我对如何创建返回的响应消息感到困惑。这是我的代码：

public class ExceptionHandlerAttribute : ExceptionFilterAttribute  
{
    public override void OnException(HttpActionExecutedContext actionExecutedContext)
    {
        actionExecutedContext.Request.CreateErrorResponse(HttpStatusCode.Accepted, new HttpError
        {
            { "Message" , "I am error"},
            { "StatusCode" , "20"}
        });
    }
}

     [AllowAnonymous]
    [HttpPost]
    [Validate]
    public IHttpActionResult Register(UserModel userRegistrationModel)
    {
        throw new AccessDeniedException("message" , new Exception("inner exception"));
    }

 public class AccessDeniedException : BaseException
{
    public AccessDeniedException(string message, Exception exception)
        : base(message, exception)
    {

    }
}

  public class BaseException : Exception
{
    public BaseException(string message , Exception exception) : base(message , exception)
    {

    }
}

现在我在myfilter配置中注册了ExceptionHandlerAttributed，在调试时我意识到OnException方法中的代码运行。

问题在于响应是这样的：

"readyState": 4,
"responseText": "{\"message\":\"An error has occurred.\",\"exceptionMessage\":\"message\",\"exceptionType\":\"CodeArt.Common.Exceptions.AccessDeniedException\",\"stackTrace\":\"   at System.Web.Http.ApiController.<InvokeActionWithExceptionFilters>d__1.MoveNext()\\r\\n--- End of stack trace from previous location where exception was thrown ---\\r\\n   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)\\r\\n   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)\\r\\n   at System.Runtime.CompilerServices.TaskAwaiter`1.GetResult()\\r\\n   at System.Web.Http.Dispatcher.HttpControllerDispatcher.<SendAsync>d__0.MoveNext()\",\"innerException\":{\"message\":\"An error has occurred.\",\"exceptionMessage\":\"inner exception\",\"exceptionType\":\"System.Exception\",\"stackTrace\":null}}",
"responseJSON": {
    "message": "An error has occurred.",
    "exceptionMessage": "message",
    "exceptionType": "CodeArt.Common.Exceptions.AccessDeniedException",
    "stackTrace": "   at System.Web.Http.ApiController.<InvokeActionWithExceptionFilters>d__1.MoveNext()\r\n--- End of stack trace from previous location where exception was thrown ---\r\n   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)\r\n   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)\r\n   at System.Runtime.CompilerServices.TaskAwaiter`1.GetResult()\r\n   at System.Web.Http.Dispatcher.HttpControllerDispatcher.<SendAsync>d__0.MoveNext()",
    "innerException": {
        "message": "An error has occurred.",
        "exceptionMessage": "inner exception",
        "exceptionType": "System.Exception",
        "stackTrace": null
    }
},
"status": 500,
"statusText": "Internal Server Error"

我没有发送异常堆栈跟踪以及与异常相关的任何其他内容。我想发送的是OnException方法中的数据集。

我做错了什么？

Answer 1

您必须将过滤器添加到全局过滤器并设置对创建的响应实例的响应：

actionExecutedContext.Response = actionExecutedContext.Request.CreateErrorResponse(HttpStatusCode.Accepted, new HttpError
    {
        { "Message" , "I am error"},
        { "StatusCode" , "20"}
    });

请注意我在一段时间内提出的关于non-consumed responses导致内存泄漏的问题。因此，您需要先执行此操作：

if(actionExecutedContext.Response != null)
    actionExecutedContext.Response.Dispose();

然后

actionExecutedContext.Response =  ...

CreateErrorResponse不会覆盖异常堆栈跟踪和消息

1 个答案: