如何评估csh shell变量

Question

#!/bin/csh
set passFail_file = "name"

set numErrs = `/bin/grep -c ERROR $passFail_file`
echo "numErrs is $numErrs"        # displays numErrs is 0, which isn't always correct
set dirLocale = `/bin/sed q $passFail_file`   #capture line 1 in file, which is nonBlank
echo "dirLocale is $dirLocale"   # displays: dirLocale is

当我运行上面的脚本时，我无法分配dirLocale。在csh中是否有等效的eval？语法是什么？我想我错过了反引号和操作顺序的混合。

Answer 1

系统表现得很奇怪。一切都很好，使用上面的语法。问题已结束。谢谢。