Question

我是zend的新手，我正在尝试使用post方法从网格中删除数据，但是当我点击“是”按钮时，它就像get方法一样工作。该网址显示了此[http://project.com/client/delete/id/10?id=10&del=Yes]。请有人帮帮我。

这是我的控制器代码。

public function deleteAction()
{

    if($this->getRequest()->isPost())
    {

        $del = $this->getRequest()->getPost('del');

         print_r($del);die;
        if($del=='Yes')
        {

          $id =$this->getRequest()->getPost('id');  

        $client = new Application_Model_DbTable_Client();

        $id = $this->getRequest()->getparam('id');

        $client->deleteClient($id);


      }

我的delete.phtml代码

您确定要删除

吗？

<?php foreach($this->client as $clients): ?>
'<?php echo $this->escape($clients['firstname']); ?>'
'<?php echo $this->escape($clients['lastname']); ?>'
'<?php echo $this->escape($clients['email']); ?>'
</p>
<?php endforeach; ?>
<form action="<?php echo $this->url(array('action'=>'delete')); ?>" method="post">
<div> 

<input type="hidden" name="id" value="<?php echo $this->escape($clients["Id"]); ?>"/>

<input type="submit" name="del" value="Yes" />
<input type="submit" name="del" value="No" />

 </div>

 </form>

Screenshot of database structure

表

array(7) {
  [0]=>
  array(4) {
["Id"]=>
string(1) "1"
["firstname"]=>
string(5) "tuhin"
["lastname"]=>
string(6) "biswas"
["email"]=>
string(15) "tuhin@gmail.com"
  }
  [1]=>
 array(4) {
["Id"]=>
string(1) "2"
["firstname"]=>
string(5) "Ankur"
["lastname"]=>
string(7) "raiyani"
["email"]=>
string(15) "Ankur@gmail.com"
  }
    [2]=>
    array(4) {
["Id"]=>
string(1) "5"
["firstname"]=>
string(5) "Tejas"
["lastname"]=>
string(5) "Patel"
["email"]=>
string(15) "tejas@gmail.com"
  }
 [3]=>
 array(4) {
 ["Id"]=>
string(1) "6"
["firstname"]=>
string(6) "Ranjan"
["lastname"]=>
string(5) "sahoo"
["email"]=>
string(16) "ranjan@gmail.com"
  }
 [4]=>
 array(4) {
["Id"]=>
string(1) "7"
["firstname"]=>
string(5) "Mansi"
["lastname"]=>
string(5) "Joshi"
["email"]=>
string(15) "mansi@gmail.com"
  }
 [5]=>
array(4) {
["Id"]=>
string(1) "8"
["firstname"]=>
string(5) "tuhin"
["lastname"]=>
string(6) "biswas"
["email"]=>
string(15) "tuhin@gmail.com"

Answer 1

我认为问题在于你将id

放在哪里

$id = $this->getRequest()->getparam('id');
$id =$this->getRequest()->getPost('id');

如果条件有不同的方式，你将在一个变量中分配两次变量。

我试图修改它可能适合您的代码，这是未经测试的。请尝试以下方法： -

控制器中的

public function deleteAction（） {

if($this->getRequest()->isPost()){
    $del = $this->getRequest()->getPost('del');

    if($del=='Yes')
    {

        $id =$this->getRequest()->getPost('Id');

        $client = new Application_Model_DbTable_Client();

        $client->deleteClient($id);
            }
    exit();


} else {
    $id = $this->_getParam('Id', 0);
    $client = new Application_Model_DbTable_Client();
            //render the id to the view         
    $this->view->clientId = $client->getClientId($id);
}

}

您的Model Dbtable客户端类。添加此方法。

            /*In your Db Client class Table*/


public function getClientId($id)
    {
        $id = (int)$id; //cast to integer.
        //here the id in your client table
        //change it  to fit it your needs
        $row = $this->fetchRow('Id = ' .$id);
        if(!$row)
        {
            throw new Exception("Could not find this $id");
        }
        return $row->toArray();

    }

并在您的ViewHTml中你确定要删除吗？

<?php foreach ($this->client as $clients) {
        echo $this->escape($clients->firstname);
        echo $this->escape($clients->lastname);                     
        echo $this->escape($clients->email);

}?>

    <form action="<?php echo $this->url(array('action'=>'delete')); ?>" method="post">

       <input type="hidden" name="Id"  value="<?php echo $this->clientId['Id']; ?>" />
       <input type="submit"name="del" value="Yes" />
       <input type="submit" name="del" value="No" />

    </form>

post方法在zend中作为get工作

1 个答案: