我正在开发一种反馈类型的应用程序,当我点击“submitnow”按钮时,我收到以下错误
活动已泄露窗口
com.android.internal.policy.impl.PhoneWindow$DecorView@46029dd0
以下是我的代码,请帮帮我。
public class SignOut_Activity extends SherlockActivity implements
OnClickListener {
Button btnSubmitNow, btnSubmitLater;
ProgressDialog progressDialog;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
getSupportActionBar().setDisplayHomeAsUpEnabled(true);
setContentView(R.layout.signout);
((TextView) findViewById(R.id.tvSubTitle))
.setText(StoresListAdapter.StoreName);
btnSubmitNow = (Button) findViewById(R.id.btnSubmitNow);
btnSubmitLater = (Button) findViewById(R.id.btnSubmitLater);
btnSubmitNow.setOnClickListener(this);
btnSubmitLater.setOnClickListener(this);
progressDialog = new ProgressDialog(SignOut_Activity.this);
progressDialog.setMessage("Uploading data, please wait...");
}
@Override
public boolean onOptionsItemSelected(
com.actionbarsherlock.view.MenuItem item) {
switch (item.getItemId()) {
case android.R.id.home:
// app icon in action bar clicked; finish activity to go home
finish();
break;
default:
break;
}
return super.onOptionsItemSelected(item);
}
@Override
public void onResume() {
super.onResume();
// Set title
getSupportActionBar().setTitle("Sign Out");
}
@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.btnSubmitNow:
// Submit now
// Sample upload image
UploadImage.uploadImage("testimage");
new AsyncTask<Void, Void, Void>() {
// called before execution // main/UI thread
protected void onPreExecute() {
progressDialog.show();
};
@Override
protected Void doInBackground(Void... params) {
// Submit the store data
StoreData.postData(StoreList_Activity.storesList
.get(StoresListAdapter.Position));
return null;
}
// on store data uploaded // main/UI thread
protected void onPostExecute(Void result) {
progressDialog.dismiss();
setSignOut();
StoreList_Activity.storesList
.get(StoresListAdapter.Position).isSubmitted = true;
SignOut_Activity.this.finish();
};
}.execute();
break;
case R.id.btnSubmitLater:
// Submit later
setSignOut();
StoreList_Activity.storesList.get(StoresListAdapter.Position).isSubmitLater = true;
VisitOps_Activity.isSubmitLater = true;
SignOut_Activity.this.finish();
break;
default:
break;
}
}
@SuppressLint("SimpleDateFormat")
private void setSignOut() {
VisitOp visitOp10 = new VisitOp();
visitOp10.setName("Sign Out");
visitOp10.setStatus("");
SampleData.visitOpsList.add(visitOp10);
if (VisitOps_Activity.VisitOps.SignOut == null)
VisitOps_Activity.VisitOps.SignOut = new SignOut();
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss");
String currentDateandTime = sdf.format(new Date());
VisitOps_Activity.VisitOps.SignOut.SignOutTime = "Out: "
+ currentDateandTime;
}
}
答案 0 :(得分:11)
泄漏是因为你在销毁之后仍然保留活动的参考所以使用
if(progressDialog !=null)
{
progressDialog = null;
}
progressDialog = new ProgressDialog(this.getApplicationContext());
progressDialog.setMessage("Uploading data, please wait...");
或强>
使用它会有所帮助
@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.btnSubmitNow:
// Submit now
// Sample upload image
UploadImage.uploadImage("testimage");
new AsyncTask<Void, Void, Void>() {
// called before execution // main/UI thread
protected void onPreExecute() {
progressDialog = new ProgressDialog(SignOut_Activity.this);
progressDialog.setMessage("Uploading data, please wait...");
progressDialog.show();
};
@Override
protected Void doInBackground(Void... params) {
// Submit the store data
StoreData.postData(StoreList_Activity.storesList
.get(StoresListAdapter.Position));
return null;
}
// on store data uploaded // main/UI thread
protected void onPostExecute(Void result) {
progressDialog.dismiss();
setSignOut();
StoreList_Activity.storesList
.get(StoresListAdapter.Position).isSubmitted = true;
SignOut_Activity.this.finish();
};
}.execute();
答案 1 :(得分:4)
为什么会出现此错误??
当您保留对未使用活动的引用时会发生此错误
解决方案
使用后删除进度条,对话框等参考。
解雇他们或使他们等于null
你可以在不再需要时接近它
推荐将其放入onStop
@Override
protected void onStop() {
super.onStop();
if(_dialog.isShowing()){
_dialog.dismiss();
}
if(_dialog != null){
_dialog = null;
}
}
答案 2 :(得分:3)
使用后忽略dialog
,它不会让您的应用程序崩溃。
dialog.dismiss();
答案 3 :(得分:2)
使用该代码progressDialog.dismiss();
答案 4 :(得分:1)
确保在对话框使用后以及任何下一个后台进程启动之前解除()对话框。