Access-Control-Allow-Origin和Angular.js $ http

时间:2013-12-24 03:31:53

标签: javascript angularjs cors

每当我制作一个webapp并且我遇到CORS问题时,我就开始煮咖啡了。拧紧它一段时间后,我设法让它工作,但这次不是,我需要帮助。

以下是客户端代码:

$http({method: 'GET', url: 'http://localhost:3000/api/symbol/junk', 
            headers:{
                'Access-Control-Allow-Origin': '*',
                'Access-Control-Allow-Methods': 'GET, POST, PUT, DELETE, OPTIONS',
                'Access-Control-Allow-Headers': 'Content-Type, X-Requested-With',
                'X-Random-Shit':'123123123'
            }})
        .success(function(d){ console.log( "yay" ); })
        .error(function(d){ console.log( "nope" ); });

服务器端是带有快速应用程序的常规node.js。我有一个名为cors的扩展名,它以这种方式表达:

var app = express();
app.configure(function(){
  app.use(express.bodyParser());
  app.use(app.router);
  app.use(cors({origin:"*"}));
});
app.listen(3000);

app.get('/', function(req, res){
    res.end("ok");
});

如果我这样做

curl -v -H "Origin: https://github.com" http://localhost:3000/

它回来了:

* Adding handle: conn: 0x7ff991800000
* Adding handle: send: 0
* Adding handle: recv: 0
* Curl_addHandleToPipeline: length: 1
* - Conn 0 (0x7ff991800000) send_pipe: 1, recv_pipe: 0
* About to connect() to localhost port 3000 (#0)
*   Trying ::1...
*   Trying 127.0.0.1...
* Connected to localhost (127.0.0.1) port 3000 (#0)
> GET / HTTP/1.1
> User-Agent: curl/7.30.0
> Host: localhost:3000
> Accept: */*
> Origin: https://github.com
>
< HTTP/1.1 200 OK
< X-Powered-By: Express
< Date: Tue, 24 Dec 2013 03:23:40 GMT
< Connection: keep-alive
< Transfer-Encoding: chunked
<
* Connection #0 to host localhost left intact
ok

如果我运行客户端代码,则会出现此错误:

OPTIONS http://localhost:3000/api/symbol/junk No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://localhost:8000' is therefore not allowed access. angular.js:7889
XMLHttpRequest cannot load http://localhost:3000/api/symbol/junk. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://localhost:8000' is therefore not allowed access. localhost/:1
nope 

检查Chromes标题:

Request URL:http://localhost:3000/api/symbol/junk
Request Method:OPTIONS
Status Code:200 OK
Request Headersview source
Accept:*/*
Accept-Encoding:gzip,deflate,sdch
Accept-Language:en-US,en;q=0.8,es;q=0.6,pt;q=0.4
Access-Control-Request-Headers:access-control-allow-origin, accept, access-control-allow-methods, access-control-allow-headers, x-random-shit
Access-Control-Request-Method:GET
Cache-Control:max-age=0
Connection:keep-alive
Host:localhost:3000
Origin:http://localhost:8000
Referer:http://localhost:8000/
User-Agent:Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/31.0.1650.63 Safari/537.36
Response Headersview source
Allow:GET
Connection:keep-alive
Content-Length:3
Content-Type:text/html; charset=utf-8
Date:Tue, 24 Dec 2013 03:27:45 GMT
X-Powered-By:Express

检查请求标题我看到我的测试字符串X-Random-Shit出现在“Access-Control-Request-Headers”中,但它的值不存在。另外,在我脑海中,我期待看到我设置的每个标题都有一行,而不是blob。

更新---

我将我的前端改为jQuery而不是Angular,并将我的后端改为:

var app = express();
app.configure(function(){
  app.use(express.bodyParser());
  app.use(app.router);
});
app.all('*', function(req, res, next) {
    res.header("Access-Control-Allow-Origin", "*");
    res.header('Access-Control-Allow-Methods', 'OPTIONS,GET,POST,PUT,DELETE');
    res.header("Access-Control-Allow-Headers", "Content-Type, Authorization, X-Requested-With");
    if ('OPTIONS' == req.method){
        return res.send(200);
    }
    next();
});

app.get('/', function(req, res){
    res.end("ok");
});

现在它适用于GET,但没有任何其他功能(PUT,POST ..)。

我会看看你们中是否有人提出了解决方案。同时将RESTful概念抛出窗口并使用GET创建所有内容。

7 个答案:

答案 0 :(得分:8)

我是AngularJS的新手,我遇到了这个CORS问题,几乎失去了理智!幸运的是我找到了解决这个问题的方法。所以这就是......

我的问题是,当我在发送API请求时使用AngularJS $资源时,我收到此错误消息XMLHttpRequest cannot load http://website.com. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://localhost' is therefore not allowed access.是的,我已经添加了callback =&#34; JSON_CALLBACK&#34;它没有用。

我做了什么来解决问题,而不是使用GET方法或诉诸$ http.get,我使用了JSONP。只需用JSONP替换GET方法,并将api响应格式也更改为JSONP。

    myApp.factory('myFactory', ['$resource', function($resource) {

           return $resource( 'http://website.com/api/:apiMethod',
                        { callback: "JSON_CALLBACK", format:'jsonp' }, 
                        { 
                            method1: { 
                                method: 'JSONP', 
                                params: { 
                                            apiMethod: 'hello world'
                                        } 
                            },
                            method2: { 
                                method: 'JSONP', 
                                params: { 
                                            apiMethod: 'hey ho!'
                                        } 
                            }
            } );

    }]);

我希望有人觉得这很有帮助。 :)

答案 1 :(得分:4)

我在表达和编辑res.header方面取得了成功。我的匹配非常接近,但我有一个不同的Allow-Headers,如下所示:

res.header("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept");

我也在使用Angular和Node / Express,但我没有在Angular代码中只调出节点/ express

答案 2 :(得分:1)

在server.js下面添加解决了我的

    server.post('/your-rest-endpt/*', function(req,res){
    console.log('');
    console.log('req.url: '+req.url);
    console.log('req.headers: ');   
    console.dir(req.headers);
    console.log('req.body: ');
    console.dir(req.body);  

    var options = {
        host: 'restAPI-IP' + ':' + '8080'

        , protocol: 'http'
        , pathname: 'your-rest-endpt/'
    };
    console.log('options: ');
    console.dir(options);   

    var reqUrl = url.format(options);
    console.log("Forward URL: "+reqUrl);

    var parsedUrl = url.parse(req.url, true);
    console.log('parsedUrl: ');
    console.dir(parsedUrl);

    var queryParams = parsedUrl.query;

    var path = parsedUrl.path;
    var substr = path.substring(path.lastIndexOf("rest/"));
    console.log('substr: ');
    console.dir(substr);

    reqUrl += substr;
    console.log("Final Forward URL: "+reqUrl);

    var newHeaders = {
    };

    //Deep-copy it, clone it, but not point to me in shallow way...
    for (var headerKey in req.headers) {
        newHeaders[headerKey] = req.headers[headerKey];
    };

    var newBody = (req.body == null || req.body == undefined ? {} : req.body);

    if (newHeaders['Content-type'] == null
            || newHeaders['Content-type'] == undefined) {
        newHeaders['Content-type'] = 'application/json';
        newBody = JSON.stringify(newBody);
    }

    var requestOptions = {
        headers: {
            'Content-type': 'application/json'
        }
        ,body: newBody
        ,method: 'POST'
    };

    console.log("server.js : routes to URL : "+ reqUrl);

    request(reqUrl, requestOptions, function(error, response, body){
        if(error) {
            console.log('The error from Tomcat is --> ' + error.toString());
            console.dir(error);
            //return false;
        }

        if (response.statusCode != null 
                && response.statusCode != undefined
                && response.headers != null
                && response.headers != undefined) {
            res.writeHead(response.statusCode, response.headers);
        } else {
            //404 Not Found
            res.writeHead(404);         
        }
        if (body != null
                && body != undefined) {

            res.write(body);            
        }
        res.end();
    });
});

答案 3 :(得分:1)

编写这个中间件可能有所帮助!

app.use(function(req, res, next) {
res.header("Access-Control-Allow-Origin", "*");
res.header("Access-Control-Allow-Headers", "Origin, X-Requested-With,     Content-Type, Accept");
next();
});

了解详情,请访问http://enable-cors.org/server_expressjs.html

答案 4 :(得分:1)

@Swapnil Niwane

我能够通过调用ajax请求并将数据格式化为'jsonp'来解决此问题。

$.ajax({
          method: 'GET',
          url: url,
          defaultHeaders: {
              'Content-Type': 'application/json',
              "Access-Control-Allow-Origin": "*",
              'Accept': 'application/json'
           },

          dataType: 'jsonp',

          success: function (response) {
            console.log("success ");
            console.log(response);
          },
          error: function (xhr) {
            console.log("error ");
            console.log(xhr);
          }
});

答案 5 :(得分:0)

我找到了一种在JSONP中直接使用$http方法并在配置对象中支持params的方法:

params = {
  'a': b,
  'callback': 'JSON_CALLBACK'
};

$http({
  url: url,
  method: 'JSONP',
  params: params
})

答案 6 :(得分:-1)

试试这个:

          $.ajax({
              type: 'POST',
              url: URL,
              defaultHeaders: {
                  'Content-Type': 'application/json',
                  "Access-Control-Allow-Origin": "*",
                  'Accept': 'application/json'
               },

              data: obj,
              dataType: 'json',
              success: function (response) {
            //    BindTableData();
                console.log("success ");
                alert(response);
              },
              error: function (xhr) {
                console.log("error ");
                console.log(xhr);
              }
          });