Question

我在使用XPath和包含函数时遇到问题。想象一下下面的XML示例：

<movie-selection>
<film> 
    <name>Hunger Games - Catching Fire</name>
    <release>2013</release>
    <description>Katniss Everdeen and Peeta Mellark are once again forced to fight for there lifes in the Hunger Games. There Victory the previous year kick starts a rebellion againist the Capitol and President Snow.  
    </description>
    <runtime>146 minutes</runtime>
    <stars>Jennifer Lawrence, Josh Hutcherson, Liam Hemsworth</stars>
    <genre>Adventure, Sci-Fi</genre>        
<rating>4.8</rating>  </film>

 <film>
    <name>Avatar</name>
    <release>2009</release>
    <description>A paraplegic Marine dispatched to the moon Pandora on a unique mission becomes torn between following his orders and protecting the world he feels is his home.  
    </description>
    <runtime>162 minutes</runtime>
    <stars> Sam Worthington, Zoe Saldana, Sigourney Weaver</stars>
    <genre>Adventure, Fantasy, Action</genre>
    <rating>4.5</rating>

我想要返回所有在动作属性中都有'动作'的电影，这是我现在拥有的，但它不起作用。任何人都可以看到我的错误吗？

movie-selection/film[contains(genre, 'Action')]

任何帮助表示感谢。

<xsl:for-each select="movie-selection/film">
    <xsl:if test="/movie-selection/film[contains(genre, &apos;Drama&apos;)]">
        <p><xsl:value-of select="name"/></p>
        <p><xsl:value-of select="release"/></p>
        <p><xsl:value-of select="runtime"/></p>
        <p><xsl:value-of select="description"/></p>
        <p><xsl:value-of select="stars"/></p>
        <p><xsl:value-of select="genre"/></p>
        <p><xsl:value-of select="rating"/></p>
    </xsl:if>
</xsl:for-each>

它会返回所有内容。

Answer 1

现在我们知道了上下文，这很容易。只需将条件放在for-each选择器中即可。

<xsl:for-each select="movie-selection/film[contains(genre, 'Drama')]">
    <p><xsl:value-of select="name" /></p>
    <!-- and so on -->
</xsl:for-each>

为什么要打扰你永远不需要的模板节点？如果你真的想在循环中使用测试，请使用此

<xsl:for-each select="movie-selection/film">
    <xsl:if test="contains(genre, 'Drama')">

xpath contains（）函数如何工作

1 个答案: