Django Url TypeError

Question

当我冲浪时：

http://127.0.0.1:8000/getEmail/getMyMessages/

我有以下错误：

getMyMessages() takes no arguments (1 given)

myapplication / urls.py包含：

urlpatterns = patterns('',
    # Examples:
    url(r'^polls/', include('polls.urls')),
    url(r'^getEmail/', include('get_new_emails.urls')),

我有一个名为'get_new_emails'的应用，get_new_emails / urls.py包含：

urlpatterns = patterns('',
    #url(r'^$', views.index, name='index')
    url(r'getMyMessages', views.getMyMessages)
)

来自get_new_emails / views.py的

：

def getMyMessages():


    from django_mailbox.models import Message

    qs = Message.objects.all()
    count = 0
    for i in qs:
        count += 1
        output = output + str(count)+ " " + i.text +'<br>' + '<br>'

    return HttpResponse(output)

我该如何解决这个问题？

Answer 1

您忘记了函数的请求参数：

def getMyMessages(request):


    from django_mailbox.models import Message

    qs = Message.objects.all()
    count = 0
    for i in qs:
        count += 1
        output = output + str(count)+ " " + i.text +'<br>' + '<br>'

    return HttpResponse(output)