Question

我想知道是否有人知道在使用此约定添加点后如何实际删除一层点：

var pointsLayer, someFeatures = [{
            //Hard coded for now
            "type": "Feature",
            "properties": {
                "name": "Company A",
                "show_on_map": true,
                "icon": 'img/violations.png'
            },
            "geometry": {
                "type": "Point",
                "coordinates": [43.22519, -107.69348]
            }
        }, {
            "type": "Feature",
           .
           .
           .
   }];
for(w=0; w < someFeatures.length; w++){
                pointsLayer = L.marker(someFeatures[w].geometry.coordinates, {icon: violations})   
                    .bindPopup("Company: "+someFeatures[w].properties.name);
                    //add map points 
                    map.addLayer(pointsLayer);
            }

典型的removeLayer（pointsLayer）;在类似的for循环中对我不起作用。但是，这并不意味着没有办法循环。我只是不确定如何。我正在尝试添加有效的点，然后在事件中删除它们（不工作）。有什么想法吗？

谢谢大家。

P.S。如果您认为这个问题相关或有帮助，请不要忘了竖起大拇指，欢呼。

Answer 1

您可以在单独的图层上添加标记（例如var markers = new L.FeatureGroup();），然后在地图（map.addLayer(markers);）上添加该图层，而不是直接在地图上添加所有标记。< / p>

例如，

http://jsfiddle.net/9BXL7/

<强> HTML

<button>remove all markers</button>
<div id="map"></div>

<强> CSS

html, body, #map {
    width: 100%;
    height: 100%;
    padding: 0;
    margin: 0;
}

<强> JS

var cloudmade = L.tileLayer('http://{s}.tile.cloudmade.com/{key}/997/256/{z}/{x}/{y}.png', {
    maxZoom: 18,
    attribution: 'Map data &copy; 2011 OpenStreetMap contributors, Imagery &copy; 2011 CloudMade',
    key: 'BC9A493B41014CAABB98F0471D759707'
});

var map = L.map('map')
    .setView([50.5, 30.51], 15)
    .addLayer(cloudmade);

var markers = new L.FeatureGroup();

function getRandomLatLng(map) {
    var bounds = map.getBounds(),
        southWest = bounds.getSouthWest(),
        northEast = bounds.getNorthEast(),
        lngSpan = northEast.lng - southWest.lng,
        latSpan = northEast.lat - southWest.lat;

    return new L.LatLng(
    southWest.lat + latSpan * Math.random(),
    southWest.lng + lngSpan * Math.random());
}

function populate() {
    for (var i = 0; i < 10; i++) {
        var marker = L.marker(getRandomLatLng(map));
        marker.bindPopup("<p>Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Donec odio. Quisque volutpat mattis eros. Nullam malesuada erat ut turpis. Suspendisse urna nibh, viverra non, semper suscipit, posuere a, pede.</p><p>Donec nec justo eget felis facilisis fermentum. Aliquam porttitor mauris sit amet orci. Aenean dignissim pellentesque.</p>", {
            showOnMouseOver: true
        });
        markers.addLayer(marker);
    }
    return false;
}

map.addLayer(markers);

populate();
function removeAllMarkers(){
    map.removeLayer(markers);
}
document.querySelector('button').onclick=function(){removeAllMarkers()};

如果您需要删除或清除标记图层以换取将来使用的点：

markers.clearLayers();

Answer 2

使用map.removeLayer()：

var circle = L.circle([lat, lng], 1000).addTo(map);
map.removeLayer(circle);

Answer 3

您可以直接在对象＆＃39; map＆＃39;。

中浏览所有图层

for ( key in map['_layers'] ){
    if(typeof map['_layers'][key]['feature'] !== 'undefined') {
        var l = map['_layers'][key];
        if( l['feature']['properties']['name'] === 'Company A' ) l.removeFrom(map);}}

去除小叶层和L.marker方法

3 个答案: