Question

请看下面的图片，我在图片中解释了我的要求。

alt text http://img30.imageshack.us/img30/5668/shippment.png

我无法在WHERE UsageTypeid IN(1,2,3,4)使用，因为它会表现为OR条件并获取所有记录。

我只想要第一张桌子的记录，这些记录附有全部4 ShipmentToID 。

结果集中不需要附加3个或更少ShipmentToID个的所有其他内容。

感谢。

Answer 1

如果(EntityId, UsageTypeId)是唯一的：

select s.PrimaryKeyField, s.ShipmentId from shipment s, item a
where s.PrimaryKeyField = a.EntityId and a.UsageTypeId in (1,2,3,4)
group by s.PrimaryKeyField, s.ShipmentId having count(*) = 4

否则，4个字段的4路连接，

select distinct s.* from shipment s, item a,  item b, item c, item d where
s.PrimaryKeyField = a.EntityId = b.EntityId = c.EntityId = d.EntityId and
a.UsageTypeId = 1 and b.UsageTypeId = 2 and c.UsageTypeId = 3 and
d.UsageTypeId = 4

你需要(EntityId, UsageTypeId)上的适当索引，所以它不会挂起......

Answer 2

这种方式比同一个表方法的多重连接更受欢迎，因为您只需修改IN子句和COUNT，而无需在列表中添加或减少更多表到查询ID更改：

select EntityId, ShipmentId
from (
    select EntityId
    from (
        select EntityId
        from EntityUsage eu
        where UsageTypeId in (1,2,3,4)
        group by EntityId, UsageTypeId
    ) b
    group by EntityId
    having count(*) = 4
) a
inner join Shipment s on a.EntityId = s.EntityId

Answer 3

如果第二个表中永远不会有UsageTypeId-EntityId组合的重复项，那么您将永远不会看到：

EntityUsageTypeId | EntityId | UsageTypeId
22685 | 4477 | 1
22687 | 4477 | 1

您可以计算该表中匹配的EntityIds。

WHERE (count(*) in <tablename> WHERE EntityId = 4477) = 4

Answer 4

DECLARE @numShippingMethods int;
SELECT @numShippingMethods = COUNT(*) 
FROM shippedToTable;

SELECT tbl1.shipmentID, COUNT(UsageTypeId) as Usages
FROM tbl2 JOIN tbl1 ON tbl2.EntityId = tbl1.EntityId
GROUP BY tbl1.EntityID
HAVING COUNT(UsageTypeId) = @numShippingMethods

在Where子句中使用（IN运算符）OR条件作为AND条件

4 个答案: