Question

我正在从推文中提取网址：

示例twitts是：

\'Whn I ws calld for ths song @VishalDadlani @5hekhar both said \"we finally hv the perfect song for u\" lulz http://t.co/6vzbyjfCGk #DramaQueen\' 


\'#FreeSunder @PMOIndia The world watches as India allows the torture of temple elephants to continue. PLEASE SHARE http://t.co/g8f1kgdasU\'
india

我希望从所有此类用户推文中获得微小的推文

我的代码：

<?php

$reg_exUrl = "/(?<![\>https?:\/\/|href=\"'])(?<http>(https?:[\/][\/]|www\.)([a-z]|[A-Z]|[0-9]|[\/.]|[~])*)/";
// The Text you want to filter for urls
$text = "Whn I ws calld for ths song lulz http://t.co/6vzbyjfCGk #DramaQueen\ ";
// Check if there is a url in the text
    if(preg_match($reg_exUrl, $text, $url))
    {
        echo preg_replace($reg_exUrl, "<a href='{$url[0]}'>{$url[0]}</a> ", $text);
    } else {       // if no urls in the text just return the text
       echo $text;
}

echo here仅显示实际的推文

这只提供一个网址，如何从推文中获取所有网址？

Answer 1

使用此正则表达式URL：

(?i)\b((?:[a-z][\w-]+:(?:/{1,3}|[a-z0-9%])|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'".,<>?«»“”‘’]))

查看source了解详情。

Answer 2

仅打印网址：

echo "<a href='{$url[0]}'>{$url[0]}</a>";

如果您想匹配所有网址，请使用preg_match_all

if(preg_match($reg_exUrl, $text, $url)) {
    preg_match_all($reg_exUrl, $text, $urls);
    foreach ($urls[0] as $url) {
        echo "<a href='{$url}'>{$url}</a><br>";
    }
} else {
    echo $text;
}

从推文中提取twitter小网址

2 个答案: