Question

我正在处理带有多个过滤器的搜索表单..但是有意想不到的结果 M使用PDO做它。并基于url创建查询...如果，对于语句

网址：lType=sale&gender=M|F&loc=can|india|asia

 SELECT * FROM table WHERE 1=1 AND type like :ltype AND location IN (:loca0) OR location IN (:loca1) OR location IN (:loca2) AND gender IN (:gend0) OR gender IN (:gend1)

所以从url我们可以理解我想得到的结果是type = sale（和）gender = m（或）f和Loc = can（或）idnia（或）asia

但没有按预期获得结果..

...谢谢

更新

由user876345审判，我试图修改我的循环以绑定位置

if(isset($_GET['loc'])){        //locations
for($i=0;$i<count($aloc);$i++){
if($i<1 && count($aloc)==1) {$sqlsl .=" AND (location IN (:loca$i))";}
else if($i<1 && count($aloc)>1 && count($aloc)!="$i" ) {$sqlsl .=" AND (location IN (:loca$i)";}
else if($i>=1 && count($aloc)>1 && count($aloc)!="$i") {    $sqlsl .=" OR location IN (:loca$i)";}
else if($i>1 && count($aloc)>1 && count($aloc)==$i+1) { $sqlsl .=")";} 
$bind['loca' . $i] = $aloc[$i];
}
}

但如果超过1个位置并输出

，则此循环不会在末尾添加)

SELECT * FROM table WHERE 1=1 AND (location IN (:loca0) OR location IN (:loca1) OR location IN (:loca2)

Answer 1

在适当的()

对中关闭条件

SELECT * FROM table WHERE 1=1 AND (type like :ltype) 
       AND (location IN (:loca0) OR location IN (:loca1) OR location IN (:loca2)) 
       AND (gender IN (:gend0) OR gender IN (:gend1))

Answer 2

将您的或/和条件与where子句中的正确括号/分组配对。

 SELECT * FROM table WHERE 1=1 
    AND type like :ltype 
    AND (location IN (:loca0) OR location IN (:loca1) OR location IN (:loca2) )
    AND (gender IN (:gend0) OR gender IN (:gend1))

使用pdo和OR的意外结果

2 个答案: