Question

在我的批处理中，我处理csv文件，在处理playerSync.exe文件时遇到错误，批处理将循环并重新启动处理csv文件后遇到问题的行。麻烦的是，对findstr的下一次调用将无法找到错误消息，即使它在那里。 tail.bat文件显示它，但是对findstr的调用无法看到它，因此打印了else消息“其他错误”并且达到了eof。或者goto loop行刚被跳过，处理以某种方式落到goto eof？ wait.bat，copycsv.bat似乎没有问题，所以我怀疑麻烦在那里。所以我的问题是为什么我不能在批处理文件中重复调用findstr找到相同的字符串？更新 - 新问题：为什么我的批处理文件中忽略了goto命令？

@echo. >> dataupdatelog.txt
@echo ============================================ >> dataupdatelog.txt
@echo %date% - %time% >> dataupdatelog.txt
@echo ============================================ >> dataupdatelog.txt
@echo. >> dataupdatelog.txt
@echo off
REM RENAME PlayerSyncLog.txt "PlayerSyncLog_%date:~-4,4%%date:~-7,2%%date:~0,2%_%time:~0,2%%time:~3,2%%time:~6,4%.TXT"

rem call download.bat >> dataupdatelog.txt
SET CSVFILE=fromwebsite.csv
REM call PlayerSync.exe -SYNC %CSVFILE%
:loop
time /T
findstr /c:"Import Successful!" "PlayerSyncLog.txt" >nul 2>&1 && (
    tail.bat
    goto success    
) || (

    findstr /c:"Error found in row" "PlayerSyncLog.txt" >nul 2>&1 && (
        echo "found exception  error"

        echo "copycsv"
        copycsv.bat
        time /T 
        RENAME PlayerSyncLog.txt "PlayerSyncLog_%date:~-4,4%%date:~-7,2%%date:~0,2%_%time:~0,2%%time:~3,2%%time:~6,4%.TXT"

        call PlayerSync.exe -SYNC %CSVFILE%
        time /T 
        echo "wait 240"
        wait.bat 240
        time /T
        echo "GOTO loop"
    GOTO loop
    echo "after GOTO loop"
) || (
    echo "some other error"
    GOTO success
))  

:success

rem call backitup.bat >> dataupdatelog.txt
rem call upload.bat >> dataupdatelog.txt
rem call uploadlogs.bat >> dataupdatelog.txt

更新代码：将/ I添加到findstr命令并添加了行echo "after goto loop"以查看goto是否被忽略，并且是“后goto循环”得到回应，例如来自运行的输出是：

C:\Documents and Settings\Administrator\Desktop\website xfer>mybatch.bat
"loop"
02:52 PM
"check for error"
"found exception  error"
(1 row affected)
"copycsv"
02:54 PM
"call playersync after error found"
02:54 PM
"wait 240"
02:58 PM
"goto loop"
"after goto loop"
C:\Documents and Settings\Administrator\Desktop\website xfer>

所以，新问题，为什么忽略goto命令？

更新2：新脚本似乎正在运行：

@echo. >> dataupdatelog.txt
@echo ============================================ >> dataupdatelog.txt
@echo %date% - %time% >> dataupdatelog.txt
@echo ============================================ >> dataupdatelog.txt
@echo. >> dataupdatelog.txt
@echo off
rem RENAME PlayerSyncLog.txt "PlayerSyncLog_%date:~-4,4%%date:~-7,2%%date:~0,2%_%time:~0,2%%time:~3,2%%time:~6,4%.TXT"

rem call download.bat >> dataupdatelog.txt
SET CSVFILE=fromwebsite.csv
rem call PlayerSync.exe -SYNC %CSVFILE%
rem echo "wait 240"
rem call wait.bat 240

GOTO BEGIN
:LOOP
echo "loop"
time /T 


call  copycsv.bat

time /T 

RENAME PlayerSyncLog.txt "PlayerSyncLog_%date:~-4,4%%date:~-7,2%%date:~0,2%_%time:~0,2%%time:~3,2%%time:~6,4%.TXT"

echo "call playersync after error found"
call PlayerSync.exe -SYNC %CSVFILE%
time /T 
echo "wait 240"
call wait.bat 240
time /T

rem END LOOP    


:BEGIN


rem tail.bat
findstr /I /c:"Import Successful!" "PlayerSyncLog.txt" >nul 2>&1 && (
    echo "success"
    SET SUCCESS=0
) || (
    echo "check for error"    
    findstr /I /c:"Error found in row" "PlayerSyncLog.txt" >nul 2>&1 && (
        echo "found exception  error"
        SET SUCCESS=1

    ) || (
        echo "some other error"
        SET SUCCESS=2
    )
)   

echo "SUCCESS==" %SUCCESS%
if %SUCCESS% == 1 ( GOTO LOOP ) else ( GOTO END )


:END

rem call backitup.bat >> dataupdatelog.txt
rem call upload.bat >> dataupdatelog.txt
rem call uploadlogs.bat >> dataupdatelog.txt

为什么我的批处理文件中忽略了goto命令？

0 个答案: