我想做的是:
class test{
public static String[][] p;
}
但是出了点问题。 当我尝试使用:
写它时p[][]={...};
它说:“p无法解析为某种类型”。
编辑: 好的,我看到理解我在说什么有一些问题所以我在这里发布了一个代码。
public class Test{
static String[][] plansza;
public static void main(String []arg){
p[][]={ {" ","A", "B", "C", "D", "E", "F", "G", "H"},
{"1.","0","1","0","1","0","1","0","1"},
{"2.","1","0","1","0","1","0","1","0"},
{"3.","0","1","0","1","0","1","0","1"},
{"4.","0","0","0","0","0","0","0","0"},
{"5.","0","0","0","0","0","0","0","0"},
{"6.","2","0","2","0","2","0","2","0"},
{"7.","0","2","0","2","0","2","0","2"},
{"8.","2","0","2","0","2","0","2","0"}
};
}
答案 0 :(得分:1)
要正常创建数组,您至少需要设置数组的第一个维度,但通常你会像
那样设置它 1)new Type[dim1][dim2]..[dimN]
如果使用
等元素初始化数组,则可以跳过维 2)new Type[][]..[]{{..{elements},},..}}
但是,如果您使用元素 在声明它的同一位置初始化数组 ,那么您可以跳过new Type[][]...[]
部分并使用{{ 1}}喜欢
3){{..{elements},},..}}
在你的情况下你有案例2)因为你没有在你声明它的位置初始化你的数组。而不是
Type[][]..[] myArray = {{..{elements},},..}}
你需要把它写成
p[][] = {
{" ","A","B","C","D","E","F","G","H"},
...
};
答案 1 :(得分:0)
尝试这种初始化:
public static String[][] s = new String[][]{
{"A", "B", "C"},
{"D", "E", "F"}
};
这将动态定义您的multidimensional Array
答案 2 :(得分:0)
您只能在初始值设定项中使用数组常量。
因此:
// will compile
public static String[][] p = {{"foo", "bar"}};
// will compile
public static String[][] p;
static {
p = new String[][]{{"foo", "bar"}};
}
// won't compile
public static String[][] p;
static {
p = {{"foo", "bar"}};
}
答案 3 :(得分:0)
了解p
是String[][]
类型的变量,因此按以下方式初始化
p = new String[][]{...};
在上面的代码p
中String[][]
类型被分配给初始化为相同类型的对象。
当您尝试分配值时,可以指定像这样的索引
p[i][j] = "value";
答案 4 :(得分:0)
尝试以下
public class Test{
static String[][] plansza;
public static void main(String []arg){
plansza = new String[][] { {" ","A", "B", "C", "D", "E", "F", "G", "H"},
{"1.","0","1","0","1","0","1","0","1"},
{"2.","1","0","1","0","1","0","1","0"},
{"3.","0","1","0","1","0","1","0","1"},
{"4.","0","0","0","0","0","0","0","0"},
{"5.","0","0","0","0","0","0","0","0"},
{"6.","2","0","2","0","2","0","2","0"},
{"7.","0","2","0","2","0","2","0","2"},
{"8.","2","0","2","0","2","0","2","0"}
};
}
}
在将new String[][]{....};
分配给planza