我有一个整数数组,需要在来自url的循环中一个接一个地调用。我有下面的代码,它会多次调用最后一个数字,但是从头开始的所有数字都被跳过。如何制作这是工作。我真的很感激任何帮助。谢谢你。
final String[] ar={"1","2","3",.............,"25"}
for ( j = 0; j < ar.length; j++) {
u="http://www.example.com/"+ar[j];
JSONParser jParser=new JSONParser();
new MyAsyncTask().execute(u);
}
class MyAsyncTask extends AsyncTask<String, String, Void> {
private ProgressDialog progressDialog = new ProgressDialog(MainActivity.this);
InputStream inputStream = null;
String result = "";
protected void onPreExecute() {
progressDialog.setMessage("Downloading your data...");
progressDialog.show();
progressDialog.setOnCancelListener(new OnCancelListener() {
public void onCancel(DialogInterface arg0) {
MyAsyncTask.this.cancel(true);
}
});
}
@Override
protected Void doInBackground(String... params) {
String url_select = params[0];
try {
HttpClient httpclient = new DefaultHttpClient();
HttpResponse httpResponse = httpclient.execute(new HttpGet(url_select));
// receive response as inputStream
inputStream = httpResponse.getEntity().getContent();
//
// // Read content & Log
// inputStream = httpEntity.getContent();
} catch (UnsupportedEncodingException e1) {
Log.e("UnsupportedEncodingException", e1.toString());
e1.printStackTrace();
} catch (ClientProtocolException e2) {
Log.e("ClientProtocolException", e2.toString());
e2.printStackTrace();
} catch (IllegalStateException e3) {
Log.e("IllegalStateException", e3.toString());
e3.printStackTrace();
} catch (IOException e4) {
Log.e("IOException", e4.toString());
e4.printStackTrace();
}
// Convert response to string using String Builder
try {
BufferedReader bReader = new BufferedReader(new InputStreamReader(inputStream, "iso-8859-1"), 8);
StringBuilder sBuilder = new StringBuilder();
String line = null;
while ((line = bReader.readLine()) != null) {
sBuilder.append(line + "\n");
}
inputStream.close();
result = sBuilder.toString();
} catch (Exception e) {
Log.e("StringBuilding & BufferedReader", "Error converting result " + e.toString());
}
return null;
} // protected Void doInBackground(String... params)
protected void onPostExecute(Void v) {
//parse JSON data
try{
JSONObject jArray = new JSONObject(result);
// End Loop
this.progressDialog.dismiss();
} catch (JSONException e) {
Log.e("JSONException", "Error: " + e.toString());
} // catch (JSONException e)
catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
} // protected void onPostExecute(Void v)
} //class MyAsyncTask extends AsyncTask<String, String, Void>
答案 0 :(得分:2)
url_select = params[0];
而不是
url_select = u;
(你在异步执行任务时在for循环中分配你,所以你不能'真正知道你有哪个值,执行任务时......最终它保留你分配的最后一个值..)
答案 1 :(得分:1)
使用
String url_select = parms[0];
如果要并行执行,则应使用执行程序。我建议你使用执行器而不是在for循环中执行asynctask。
new MyAsyncTask().executeOnExecutor(AsyncTask.THREAD_POOL_EXECUTOR, "url1","url2"..);
http://developer.android.com/reference/android/os/AsyncTask.html#executeOnExecutor(java.util.concurrent.Executor,Params ......)
检查执行顺序@
http://developer.android.com/reference/android/os/AsyncTask.html
答案 2 :(得分:1)
String url_select = u;
我认为问题在于你在这里使用硬编码值你应该从params
获得传递的值
String url_select = params[0];