Question

如果我加入两张桌子，我会得到下表

SELECT a.Category, a.categoryid, b.parentid,b.Level
FROM a JOIN b ONa.CatId=b.Catid

实际数据： -

  Category               Catid         ParentID      Level
  -----------------------------------------------------------
  Pumps & Accss             20               0           0                                            
  Inground Pumps           213               20          1
  Above Ground             215               20          1                                              
  Commercial Pumps         216               20          1 
  Hawrd super pumps        814               213         2 
  Hywrd north pumps        815               213         2

这是一个使用游标的示例我必须像所有类别ID一样应用...

我需要像这样显示这些数据：

  Cat1               Cat2           Cat3             ItemNo
  ------------------------------------------------------------
  Pumps & Accss      Above Ground   Hawrd super      AX007123 
  Pumps & Accss      Above Ground   Hywrd north      AX0071201 
  Pumps & Accss      Commercial Pu  Hawrd super      AX007754  
  Pumps & Accss      Commercial Pu  Hawrd super      AX0077891 
  Pumps & Accss      Inground Pumps Hywrd north      AX0071251

Cat1列中的级别1和Cat2列中的级别2，如此

需要获得输出。像这样我有10个级别，请发布一些好的答案解决这个问题。

Answer 1

检查一下......您可以多次使用同一个表来构建多级联接

declare @category table(categoryId int, category char(100), principalId int)
declare @article table(articleId int, article varchar(100), categoryId int)

insert into @category(categoryId, category, principalId)
values (1,'One', null)

insert into @category(categoryId, category, principalId)
values (2,'two', null)

insert into @category(categoryId, category, principalId)
values (11,'eleven', 1)

insert into @category(categoryId, category, principalId)
values (21,'twenty one', 2)

insert into @category(categoryId, category, principalId)
values (22,'twenty two', 2)

insert into @category(categoryId, category, principalId)
values (111,'one hundred eleven', 11)

insert into @category(categoryId, category, principalId)
values (211,'two hundred eleven', 21)

insert into @category(categoryId, category, principalId)
values (221,'two hundred twenty one', 22)

insert into @category(categoryId, category, principalId)
values (2211,'two thousand two hundred twenty one', 221)

insert into @article(articleId, article, categoryId)
values (1, 'Article 1', 111)

insert into @article(articleId, article, categoryId)
values (2, 'Article 2', 211)

insert into @article(articleId, article, categoryId)
values (3, 'Article 3', 221)

insert into @article(articleId, article, categoryId)
values (4, 'Article 4', 2211)

select coalesce(c5.category,'') c5,
    coalesce(c4.category,'') c4,
    coalesce(c3.category,'') c3,
    coalesce(c2.category,'') c2,
    coalesce(c1.category,'') c1,
    a.article
from @article a
    left join @category c1 on c1.categoryId = a.categoryId
    left join @category c2 on c2.categoryId = c1.principalId
    left join @category c3 on c3.categoryId = c2.principalId
    left join @category c4 on c4.categoryId = c3.principalId
    left join @category c5 on c5.categoryId = c4.principalId

如果你共享表定义，它有助于改善我的答案，希望有助于你指出正确的方向

需要使用SQL Server 2008显示如下格式的数据

1 个答案: