Question

我有这样的json值，我尝试使用每个来获得结果一个一个，但它没有回到我身上

"[{"id":6,"userid":13,"title":"business3","bussinessTypeid":1,"photurl":"","cntry":[{"id":"9","name":"Bahrain"}]},

{"id":7,"userid":13,"title":"business6 arabic","bussinessTypeid":1,"photurl":"","cntry":[{"id":"1","name":"Afghanistan"}]},

{"id":10,"userid":13,"title":"E-commerce","bussinessTypeid":1,"photurl":"","cntry":[{"id":"1","name":"Afghanistan"}]},

{"id":11,"userid":8,"title":"Auto phone parts","bussinessTypeid":1,"photurl":"","cntry":[{"id":"1","name":"Afghanistan"}]},

{"id":19,"userid":8,"title":"التجارة الإلكترونية","bussinessTypeid":1,"photurl":".jpg","cntry":[{"id":"9","name":"Bahrain"}]},

{"id":20,"userid":8,"title":"E-commerce -online shopping","bussinessTypeid":8,"photurl":".jpg","cntry":[{"id":"9","name":"Bahrain"}]},

{"id":21,"userid":13,"title":"My new Business","bussinessTypeid":6,"photurl":".jpg","cntry":[{"id":"9","name":"Bahrain"}]}]"

任何人都可以指导我实现这个

Answer 1

使用parseJson()

描述：采用格式正确的JSON字符串并返回结果 JavaScript对象。

Answer 2

我认为它被视为一个字符串，尝试删除它的开头和结尾处的（“）：

var json = [{"id":6,"userid":13,"title":"business3","bussinessTypeid":1,"photurl":"","cntry":[{"id":"9","name":"Bahrain"}]},{"id":7,"userid":13,"title":"business6 arabic","bussinessTypeid":1,"photurl":"","cntry":[{"id":"1","name":"Afghanistan"}]},{"id":10,"userid":13,"title":"E-commerce","bussinessTypeid":1,"photurl":"","cntry":[{"id":"1","name":"Afghanistan"}]},{"id":11,"userid":8,"title":"Auto phone parts","bussinessTypeid":1,"photurl":"","cntry":[{"id":"1","name":"Afghanistan"}]},{"id":19,"userid":8,"title":"التجارة الإلكترونية","bussinessTypeid":1,"photurl":".jpg","cntry":[{"id":"9","name":"Bahrain"}]},{"id":20,"userid":8,"title":"E-commerce -online shopping","bussinessTypeid":8,"photurl":".jpg","cntry":[{"id":"9","name":"Bahrain"}]},{"id":21,"userid":13,"title":"My new Business","bussinessTypeid":6,"photurl":".jpg","cntry":[{"id":"9","name":"Bahrain"}]}];

然后进行迭代：

for(id in json){
 alert(json[id]['id']);
}

并且不包括任何下一行空格，只要它们用逗号分隔（，）

Answer 3

$.each(data, function(key, value){
 console.log(value.id, value.title);
  $.each(value.cntry, function(key2, value2){
    console.log(value2.id, value2.name);
  })
});

使用jquery

尝试此操作

var data = jQuery.parseJSON(yourJsonInString); //or this parser below
var data = JSON.parse(yourJsonInString);

如何在json中返回这些数据？

3 个答案: