我目前正在开发一个python项目,我需要它在某个时候接受用户的随机输入。
所以,如果我有,例如:
def question_one () :
answer_one = raw_input ('How many days are there in a week? ').lower()
try:
if answer_one == 'seven' or answer_one == '7' :
question_2()
一切都有奇效。但是如何让python接受随机输入,如
def question_two () :
answer_two = raw_input ('What´s your mother´s name? ').lower()
try:
if answer_two == ***I have no idea how to code this part*** :
question_3()
在这种情况下,我需要python接受任何输入,并仍然将用户带到下一个问题。我怎么能这样做?
答案 0 :(得分:4)
然后删除if子句。
答案 1 :(得分:3)
如果输入不必是特定形式,或具有某些特定属性,则不需要if
语句,甚至try
。
def question_two():
answer_two = raw_input("What's your mother's name?").lower()
question_3()
答案 2 :(得分:1)
如果您希望能够重新提出问题,如果他们没有做到正确,那么您可以像这样循环回来。这个问题唯一可接受的答案是“是”,或“是”等。 如果他们没有正确回答,他们会再次问他们,直到他们做对了。
def question1():
answer1 = raw_input("Do you like chickens?")
answer1 = answer1.lower()
if answer1 == 'yes':
print "That is Correct!"
question2()
else:
question1()
如果你希望他们能够继续下一个问题,即使他们弄错了,你可以这样做:
def question1():
answer1 = raw_input("Do you like chickens?")
answer1 = answer1.lower()
if answer1 == 'yes':
print "That is Correct!"
else:
print "Next question coming!"
question2()
def question2():
answer2 = raw_input("How many days in a week?")
answer2 = answer2.lower()
if answer2 == '7' or answer2 == "seven":
print "That is Correct!"
else:
print "Sorry,that was wrong"
question3()