Question

我使用jasper在openerp创建了2个报告。但是我对2个报告使用相同的解析器，第一个报告是“详细报告”，第二个报告是“摘要”。在附加到结果列表的字典（命名数据）中，有密钥日期，发票，借方和贷方。对于详细报告，我只需要从account.move.line获取这些值。但是对于摘要报告，只有一行包含相同发票号的帐户移动行。那就是我需要添加具有相同发票号的帐户移动行的借方和贷方，并将其显示为一行，我该如何在Python中执行。例如，结果列表是

[{'invoice':1,'debit':10,'credit':10},
 {'name':'b','invoice':2,'debit':10,'credit':18},
 {'invoice':1,'debit':10,'credit':10}]

我需要的是

[{'invoice':1,'debit':20,'credit':20},
 {'invoice':2,'debit':10,'credit':18}]

修改代码是

move_line_ids = move_line_pool.search(cr, uid, domain, context=context)
        print 'move_line_ids', len(move_line_ids)

        for move_line in move_line_pool.browse(cr, uid, move_line_ids, context=context):
            group_by = grp = grp_acc = ''
            debit = credit = bal = 0.0
            if move_line.debit > 0.0:
                debit = move_line.amount_residual
            elif move_line.credit > 0.0:
                credit = move_line.amount_residual
            bal = debit - credit    
            if form_group_by == 'group_account_code':
                group_by = 'ACCOUNT CODE : '
                grp = move_line.account_id.code or ''
                grp_acc = move_line.account_id.name or ''
            elif form_group_by == 'group_order_no':
                group_by = 'ORDER : '
                grp = move_line.sale_id.name or ''
            else:
                group_by = 'INVOICE : '
                grp = move_line.invoice.number or ''
            date = dt.strptime(str(move_line.date), '%Y-%m-%d').strftime('%d-%m-%Y')

            data = {
                        'period': period,
                        'date': date,
                        'company': company or '',
                        'so': move_line.sale_id.name or '',
                        'invoice': move_line.invoice.number or '',
                        'po': '',
                        'status': '',
                        'ref': move_line.move_id.name or '',
                        'debit': debit,
                        'credit': credit,
                        'bal': bal,
                        'fc': '',
                        'f_amt': '',
                        'trx': move_line.journal_id.code or '',
                        'account': move_line.account_id.name or '',
                        'account_code': move_line.account_id.code or '',
                        'acc_range': acc_range,
                        'group_by': group_by,
                        'grp': grp,
                        'grp_acc': grp_acc,
            }

            result.append(data)

        if form_group_by == 'group_account_code':
            result = sorted(result, key=lambda k: k['account_code'])
        elif form_group_by == 'group_order_no':
            result = sorted(result, key=lambda k: k['so'])
        else:
            result = sorted(result, key=lambda k: k['invoice'])
        return result

只考虑字典中的密钥invoice,debit and credit，如果发票相同，则不需要更新其他密钥。

Answer 1

假设我理解你的问题，这样的事情可以解决问题：

sum_dict = {}

for e in source_list:
    if e["invoice"] in sum_dict.keys():
        sum_dict[e["invoice"]]["debit"]+=e["debit"]
        sum_dict[e["invoice"]]["credit"]+=e["credit"]
    else:
        sum_dict[e["invoice"] = e

result_list = [sum_dict[k] for k in sum_dict.keys()]

<强> ETA：

在添加代码之前，我回答了基本问题。将更新。

ETA 2：

好的，我认为这是一个简单的修复，可以在for循环和if / else块之间运行。

但是，正如评论者指出的那样，最好的修复方法可能是对db调用的逻辑进行一些更改。但是我不知道那里有什么好的改变。

Answer 2

可能不是优化的答案......

li_dict =[{'invoice':1,'debit':10,'credit':10},{'name':'b','invoice':2,'debit':10,'credit':18},
{'invoice':1,'debit':10,'credit':10}, {'name':'b','invoice':2,'debit':10,'credit':18}]


final_result = []
for dic in li_dict :
    temp_dict = {}
    flag = False

    for dic_f in final_result:
        if 'invoice' in dic and 'invoice' in dic_f:
            if dic['invoice'] == dic_f['invoice']:
                dic_f['debit'] = dic['debit'] + dic_f['debit']
                dic_f['credit'] = dic['credit'] + dic_f['credit']
                flag = True
                break

    if not flag:
        temp_dict['invoice'] = dic.get('invoice', 0)
        temp_dict['debit'] = dic.get('debit', 0)
        temp_dict['credit'] = dic.get('credit', 0)
        final_result.append(temp_dict)

print final_result

结果：

[{'credit': 20, 'invoice': 1, 'debit': 20}, {'credit': 18, 'invoice': 2, 'debit': 10}]

如何根据另一个值在python字典中添加（求和）这两个值？

2 个答案: