Question

这是我的代码。我从我的数据库中得到一个blob。哪个像这样返回给我：java.io.BufferedInputStream@16e31e37。现在我试图在浏览器中显示来自我的servlet的图像，但是我的BufferedImage图像始终为null。我对它进行了调整，并注意到我的斑点长度始终为34 ..无论图像如何。

@Path("/photo" )
public class DisplayPhoto { 

@GET
@Path("{id}")
 @Produces("image/*")
public Response post(@PathParam("id") String id) throws IOException {
    Connection con = connection();
    Blob blob = getPhoto(con);




    int blobLength = 0;
    try {
        blobLength = (int) blob.length();
    } catch (SQLException e2) {
        // TODO Auto-generated catch block
        e2.printStackTrace();
    }  
    byte[] data = null;
    try {
        data = blob.getBytes(1, blobLength);
    } catch (SQLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
    BufferedImage image = null;
    try {
    image = ImageIO.read(new ByteArrayInputStream(data));
//  ImageIO.write(image, "JPEG", new File("C:/Users/Nicolas/Desktop")); // writing image to some specific folder.

    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }



    return Response.ok(image).build();

}



public Connection connection(){
    Connection con = null;

    try {// set up driver for database
        Class.forName("com.mysql.jdbc.Driver");
    } catch (ClassNotFoundException e) {
        e.printStackTrace();
    }


    try {
        con = DriverManager.getConnection("jdbc:mysql://aa1c9da17owdhky.cotr7twg0ekb.us-west-2.rds.amazonaws.com/test","nightskycode","uocb4t111");
    //  boolean reachable = con.isValid(10);// check for connection to DB


    } catch (SQLException e) {
        e.printStackTrace();
        System.out.println("No go!3");
    }
    return con;
  }

public Blob getPhoto(Connection con){

    Blob photo = null;
    Statement stmt = null;
    ResultSet rs = null;


    try {
        stmt = con.createStatement();
        rs = stmt.executeQuery("Select photo from photos where photo_id = 7");

        if (stmt.execute("Select photo from photos where photo_id = 7")) {
            rs = stmt.getResultSet();

            while (rs.next()) { // results here
           photo =  rs.getBlob("photo");
            System.out.println(rs.getString("photo")); }
        }

    } 
    catch (SQLException ex){
        // handle any errors
        System.out.println("SQLException: " + ex.getMessage());
        System.out.println("SQLState: " + ex.getSQLState());
        System.out.println("VendorError: " + ex.getErrorCode());
    }
    return photo;

}

以下是我将数据上传到数据库的方法

@Path("/submitinfo" )
public class SubmitName {   

@POST
@Produces(MediaType.APPLICATION_XML)
@Consumes(MediaType.APPLICATION_FORM_URLENCODED)
public String post(@FormDataParam("file") InputStream uploadedInputStream, @FormParam("first") String name) {
    Connection con = connection();

    postName(con, name);
    postPhoto(con, uploadedInputStream);
    return name; 


}


public void postPhoto(Connection con, InputStream uploadedInputStream){


    Statement stmt = null;
    String updateQuery = "INSERT INTO photos (photo) values ('" + uploadedInputStream + "')" ;
    System.out.println(updateQuery);

    try {
        stmt = con.createStatement();
        stmt.executeUpdate(updateQuery);
        con.close(); // Close the connection

    } catch (SQLException e) {
        e.printStackTrace();

    }

}

Answer 1

问题是你如何尝试将数据存储为blob。您需要使用PreparedStatement - 具体来说，使用setBlob()方法：

String mySQL = "INSERT INTO photos (photo) values (?)";
PreparedStatement pStmt = con.prepareStatement(mySQL);
pStmt.setBlob(1, uploadedInputStream);
pStmt.execute();

编辑添加：它现在无法正常工作的原因是因为您正在连接String以创建您的SQL并且您获得了{{1}的结果这是你看到的存储 - 它是默认的InputStream.toString()，它是类名和哈希码的组合。

实际上你总是使用Object.toString()。它不仅可以实现更清晰的代码，还可以为您处理引用/转义，而不易出错。

ImageIO.read在字节数组上返回null

1 个答案: