我有一个带有ImageView和textView的简单列表视图。
现在每当我点击我的listItem时,我都需要将ImageView发送到另一个活动。
我已阅读了许多SO答案,但无法找到更好的解决方案。
这是我的lisview_items.xml:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="wrap_content">
<LinearLayout
android:layout_width="wrap_content"
android:layout_height="match_parent"
android:orientation="vertical">
<ImageView
android:id="@+id/photo"
android:layout_width="150dip"
android:layout_height="100dip"
android:paddingRight="15dp"
android:paddingLeft="15dp"/>
</LinearLayout>
<RelativeLayout
android:layout_width="fill_parent"
android:layout_height="match_parent"
android:orientation="vertical"
android:layout_marginLeft="160dp"
android:layout_marginTop="10dp"
android:descendantFocusability="blocksDescendants">
<TextView android:id="@+id/name"
android:textSize="14sp"
android:textStyle="bold"
android:textColor="#000000"
android:layout_width="wrap_content"
android:layout_height="wrap_content"/>
</RelativeLayout>
<RelativeLayout>
CustomAdapter:
public View getView(final int position, View convertView, ViewGroup parent) {
ViewHolder holder;
if (convertView == null) {
convertView = l_Inflater.inflate(R.layout.item_details_view, null);
holder = new ViewHolder();
holder.txt_itemName = (TextView) convertView.findViewById(R.id.name);
holder.itemImage = (ImageView) convertView.findViewById(R.id.photo);
convertView.setTag(holder);
} else {
holder = (ViewHolder) convertView.getTag();
}
holder.txt_itemName.setText(itemDetailsrrayList.get(position).getName());
holder.itemImage.setImageResource(imgid[itemDetailsrrayList.get(position).getImageNumber() - 1]);
}
MyListView OnClick:
ArrayList<ItemDetails> image_details = GetSearchResults();
final ListView lv1 = (ListView) findViewById(R.id.list);
lv1.setAdapter(new ItemListBaseAdapter(this, image_details));
OnItemClickListener itemClickListener = new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> a, View v, int position, long id) {
Object o = lv1.getItemAtPosition(position);
ItemDetails obj_itemDetails = (ItemDetails)o;
Toast.makeText(ListViewImagesActivity.this, "You have chosen : " + " " + obj_itemDetails.getName(), Toast.LENGTH_LONG).show();
ProductName =obj_itemDetails.getName();
}
};
我使用共享偏好来发送产品名称,如下所示,它可以正常使用
SharedPreferences data = PreferenceManager.getDefaultSharedPreferences(getBaseContext());
data.edit().putString("SelectedProduct", ProductName).commit();
以类似的方式,如何将图像发送到ArrayList中,如上所示。任何人都可以告诉我这个用法的一些说明
答案 0 :(得分:0)
您可以将图像路径存储在ItemDetails
对象上,就像使用名称一样。然后,您可以通过Intent
将路径传递给新的Activity
。
如果图片在编译时可用,你可以像Gabe所说的那样传递对id的引用,而不是它的位置路径。
答案 1 :(得分:0)
如果您实际切换到该活动,则可以在intent extras中传递图像的资源ID,然后在那里使用getResources().getDrawable(ID)
。
答案 2 :(得分:0)
您应该执行以下操作:
final ArrayList<ItemDetails> image_details = GetSearchResults();
final ListView lv1 = (ListView) findViewById(R.id.list);
lv1.setAdapter(new ItemListBaseAdapter(this, image_details));
OnItemClickListener itemClickListener = new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> a, View v, int position, long id) {
ItemDetails selectedItem = image_details.get(position);
//To-DO get you data from the ItemDetails Getter
// selectedItem.getImage() or selectedItem.getName() .. etc
// the send the data using intent when opening another activity
Intent intent = new Intent(CurrentActivity.this, DisplayImageActivity.class);
intent.putExtra("image",selectedItem.getImage());
intent.putExtra("name",selectedItem.getName());
startActivty(intent);
}
};
然后在OnCreate的DisplayImageActivity中
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
Intent i = getIntent();
String image = i.getStringExtra("image");
String name = i.getStringExtra("name");
}