Question

我在使用Django-Tastypie制作的API中创建了一个资源，它根据作为url参数提供的哈希值返回单个对象。到目前为止，一切都按预期工作，但资源只返回一个具有单个对象的数组，而不是只返回一个JSON对象。因为我想将资源连接到Backbone-Model，所以只拥有该对象会更方便。

资源：

class ObjectResource(CommonResource):
    class Meta(CommonResource.Meta):
        queryset = ObjectModel.objects.all()
        resource_name = 'object'
        allowed_methods = ['get']
        authorization = Authorization()

    def obj_create(self, bundle, **kwargs):
        return super(ObjectResource, self).obj_create(bundle, hash_value=self.hash_value)

    def authorized_read_list(self, object_list, bundle):
        return object_list.filter(hash_value=self.hash_value)

Json回复

[{"app_enabled": false, "enable_global_note": false, "enable_guest_order_notes": true, "enable_guest_orders": false, "enable_in_house": false, "guest_orders_active": false, "hash_value": "33d96c3c094b54dd918407c3ef79b219", "id": 34, "name": "SpÃ¤tzlerei", "resource_uri": "", "slug": "spaetzlerei", "state": 0, "time_added": "2013-08-01T20:11:34.689550", "time_modified": "2013-08-06T10:37:01.907677", "vendor": "myorderbird"}]

Json回应通缉：

{"app_enabled": false, "enable_global_note": false, "enable_guest_order_notes": true, "enable_guest_orders": false, "enable_in_house": false, "guest_orders_active": false, "hash_value": "33d96c3c094b54dd918407c3ef79b219", "id": 34, "name": "SpÃ¤tzlerei", "resource_uri": "", "slug": "spaetzlerei", "state": 0, "time_added": "2013-08-01T20:11:34.689550", "time_modified": "2013-08-06T10:37:01.907677", "vendor": "myorderbird"}

有关如何实现这一目标的任何指示都将受到高度赞赏。

Answer 1

您必须使用authorized_read_detail而不是authorized_read_list才能检索单个对象而不是包含一个对象的列表。

返回单个对象而不是数组

1 个答案: