Question

好的，所以我正在尝试使用纯PHP制作日历。我想添加两个箭头，允许用户前进和后退几个月。当它下降到第一个月或直到第12个月时，它还需要自动更改年份。

我已经得到以下代码，认为它可以与get paramaters一起工作，但我开始认为没有使用$_GET['']有更好的方法。

<td class='calendar-day-head'><a href='Menu.php?month=".--$month."&year=2013' class='btn btn-primary'><span class='glyphicon glyphicon-chevron-left'></span></a></td>
<td class='calendar-day-head' colspan='5' style='vertical-align:middle;'>" .$month_full_text. " " .$year. "</td>
<td class='calendar-day-head'><a href='Menu.php?month=".++$month."&year=2013' class='btn btn-primary'><span class='glyphicon glyphicon-chevron-right'></span></a></td></tr>";

现在我有一个if语句所以日历仍然加载没有参数:(这是在Menu.php中）

if (!$_GET['month'] || !$_GET['year']) {

  $month = date('m');
  $year = date('y');
}
else {

  $month = $_GET['month']; 
  $year = $_GET['year'];
}

echo draw_calendar($month,$year);

我制作日历和获取菜单项的完整代码如下:(这是在menu-controller.php中）

function draw_calendar($month,$year){

require '../system/config/config.php';

/* draw table */
$calendar = '<table class="table table-bordered">';

/* get full month text */ 
$result = mysqli_query($con,"SELECT * FROM months WHERE month_number=$month");

if (mysqli_num_rows($result) > "0") {

    while($row = mysqli_fetch_array($result)) {

        extract($row);

        $calendar .= "<tr class='calendar-row'>
            <td class='calendar-day-head'><a href='Menu.php?month=".--$month."&year=2013' class='btn btn-primary'><span class='glyphicon glyphicon-chevron-left'></span></a></td>
            <td class='calendar-day-head' colspan='5' style='vertical-align:middle;'>" .$month_full_text. " " .$year. "</td>
            <td class='calendar-day-head'><a href='Menu.php?month=".++$month."&year=2013' class='btn btn-primary'><span class='glyphicon glyphicon-chevron-right'></span></a></td></tr>";
    }
}

/* table headings */
$headings = array('Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday');
$calendar.= '<tr class="calendar-row"><td class="calendar-day-head">'.implode('</td><td class="calendar-day-head">',$headings).'</td></tr>';

/* days and weeks vars now ... */
$running_day = date('w',mktime(0,0,0,$month,1,$year));
$days_in_month = date('t',mktime(0,0,0,$month,1,$year));
$days_in_this_week = 1;
$day_counter = 0;
$dates_array = array();

/* row for week one */
$calendar.= '<tr class="calendar-row">';

/* print "blank" days until the first of the current week */
for($x = 0; $x < $running_day; $x++):
    $calendar.= '<td class="calendar-day-np"> </td>';
    $days_in_this_week++;
endfor;

/* keep going with days.... */
for($list_day = 1; $list_day <= $days_in_month; $list_day++):
    $calendar.= '<td class="calendar-day" height="100">';
        /* add in the day number */
        $calendar.= '<div class="day-number">'.$list_day.'</div>';

        /** Query the database for an entry for this day !! If matches found, print them !! **/
        $result = mysqli_query($con,"SELECT * FROM menu_items WHERE month=$month AND year=$year AND day = $list_day");

        if (mysqli_num_rows($result) > "0") {

            while($row = mysqli_fetch_array($result)) {

                extract($row); 

                $calendar .= "<b>" .$entree. "</b><br/>";
                $calendar .= "" .$side_one. "<br/>";
                $calendar .= "" .$side_two. "<br/>";
                $calendar .= "" .$dessert. ""; 
            }
        }

        else {

            $calendar .= "";
        }

    $calendar.= '</td>';
    if($running_day == 6):
        $calendar.= '</tr>';
        if(($day_counter+1) != $days_in_month):
            $calendar.= '<tr class="calendar-row">';
        endif;
        $running_day = -1;
        $days_in_this_week = 0;
    endif;
    $days_in_this_week++; $running_day++; $day_counter++;
endfor;

/* finish the rest of the days in the week */
if($days_in_this_week < 8):
    for($x = 1; $x <= (8 - $days_in_this_week); $x++):
        $calendar.= '<td class="calendar-day-np"> </td>';
    endfor;
endif;

/* final row */
$calendar.= '</tr>';

/* end the table */
$calendar.= '</table>';

/* all done, return result */
return $calendar;
    }

My calendar so you can understand what I'm trying to do better.

更新所以我的问题是，当用户点击菜单顶部的左右箭头时，如何使用我已经拥有的脚本动态增加和减少月份和年份？现在我正在使用$_GET['']因为很多原因而无法正常工作：

当月份变为1时，它可以降至0并且年份不会改变。上一年应该从1到12。
它使用易受攻击的$_GET['']
++$month减少月份而不是增加月份。

基本上，我希望增加和减少用户在不使用URL的情况下单击前进和上一个按钮的月份和年份。就像你可以使用谷歌日历。（不，我不能只使用谷歌日历。）

Answer 1

谷歌日历使用AJAX我猜你不会在浏览器URL中看到params。在解决方案中使用GET参数应该没问题。

//get the 1st of currently opened month
$currentMonth = strtotime($year . '-' . $month . '-01');

//get the 1st of previous and next months
$prevMonth = strtotime('-1 month', $currentMonth);
$nextMonth = strtotime('+1 month', $currentMonth);

//get the url (GET) params for prev and next months
$prevMonthParams = 'year=' . date('Y', $prevMonth) . '&month=' . date('m', $prevMonth);
$nextMonthParams = 'year=' . date('Y', $nextMonth) . '&month=' . date('m', $nextMonth);

//use them in the url you need

我相信这段代码可以帮助你。

在您根据需要打开月份之前，您应该对“现有”或“允许”日期进行所有检查。但是在URL中使用年份和月份应该不是问题。

您将获得的唯一“漏洞”是用户可以手动输入值并以这种方式跳转到月份而不是单击箭头（只要您确保输入值如前所述有效）。

使用href浏览日历月份

1 个答案: