我正在开发一个使用jquery＆amp; amp;存储数据到数据库的应用程序。 JSON。
我的剧本功能：
<script type="text/javascript">
function test() {
$(document).ready(function () {
var Email = document.getElementById('<%= txtEmail.ClientID %>').value;
var Message = document.getElementById('<%= txtMessage.ClientID %>').value;
var Name = document.getElementById('<%= txtMessage.ClientID %>').value;
var ID=32;
$.ajax({
type: "POST",
url: "Detail.aspx/InsertMethod",
data: "{'Name':'" + Name + "'Email:'" + Email + "'Message:'" + Message + "'ID:'"+ID+"'}",
dataType: "json",
contentType: "application/json; charset=utf-8",
success: function (data) {
var returnedstring = data.d;
}
});
});
}
</script>
我的设计是： -
<table>
<tr>
<td>
<label>Name</label>
</td>
<td>input type="text" id="txtName" runat="server" class="form-control">
<asp:RequiredFieldValidator ID="RequiredFieldValidator5" runat="server" ControlToValidate="txtName"
Display="Dynamic" SetFocusOnError="true" ErrorMessage="Enter Name." ValidationGroup="Comment">
</asp:RequiredFieldValidator>
</td>
</tr>
<tr>
<td>
<label>Email</label>
</td>
<td>asp:TextBox ID="txtEmail" runat="server" CssClass="form-control"></asp:TextBox>
<asp:RequiredFieldValidator ID="RequiredFieldValidator3" runat="server" ControlToValidate="txtEmail"
Display="Dynamic" SetFocusOnError="true" ErrorMessage="Enter Email." ValidationGroup="Comment">
</asp:RequiredFieldValidator>
<asp:RegularExpressionValidator ID="RegularExpressionValidator1" runat="server" ControlToValidate="txtEmail"
SetFocusOnError="true" ValidationExpression="^[a-z0-9_\+-]+(\.[a-z0-9_\+-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*\.([a-z]{2,4})$"
ErrorMessage="Invalid Email-Id"></asp:RegularExpressionValidator>
</td>
</tr>
<tr>
<td>
<label>Message</label>
</td>
<td>
<textarea class="form-control" rows="8" id="Textarea1" runat="server"></textarea>
<asp:RequiredFieldValidator ID="RequiredFieldValidator4" runat="server" ControlToValidate="txtMessage"
Display="Dynamic" SetFocusOnError="true" ErrorMessage="Enter Message." ValidationGroup="Comment">
</asp:RequiredFieldValidator>
</td>
</tr>
<tr>
<td></td>
<td>
<button class="btn-ps" type="submit" id="btnSave" validationgroup="Comment" onclick="test()">Send Message</button>
</td>
</tr>
</table>
我的网络方法是： -
[System.Web.Script.Services.ScriptMethod()]
[System.Web.Services.WebMethod(enableSession: true)]
public static string InsertMethod(string Name, string Email,string Message,sting ID)
{
int retval = 0;
try
{
Entity_NewsComments objComment = new Entity_NewsComments();
objComment.ID= ID;
objComment.Comment = Message;
objComment.Email = Email;
objComment.Name = Name;
if ((!string.IsNullOrEmpty(objComment.Email)) && (!string.IsNullOrEmpty(objComment.Name)) && (!string.IsNullOrEmpty(objComment.Comment)))
{
objComment.QFlag = "I";
objComment.Date = Convert.ToDateTime(DateTime.Now.ToString());
objComment.Status = 0;
//retval = new Process_NewsComments().insert(objComment);
if (retval > 0)
{
}
}
return "true";
}
catch (Exception ex)
{
throw (ex);
}
}
但它没有用。我已经在网络方法上放了一个调试器，但它不会去那里。它也没有显示任何错误。请帮助我
答案 0 :(得分：1)
document.ready不是通过这种方式使用..无论如何你可以直接调用该函数。我在你的问题中观察到了很多事情
纠正上面的事情并尝试一次。
你的javascript方法应该如下
<script type="text/javascript">
function test() {
var Email = $('Your Email field client ID').val();
var Message = $('Your message field client ID %>').val();
var Name = $('Your Name field client ID').val();
var ID=32;
$.ajax({
type: "POST",
url: "Detail.aspx/InsertMethod", //URL should be fully qualified
data: "{'Name':'" + Name + "'Email:'" + Email + "'Message:'" + Message + "'ID:'"+ID+"'}",
dataType: "json",
contentType: "application/json; charset=utf-8",
success: function (data) {
var returnedstring = data.d;
},
error: function(a)
{ alert(a.responseText);}
});
}
</script>
答案 1 :(得分：0)
这是 insert data into the database 的另一种好方法，而不是发送字符串参数。我发送Javascript对象并在服务器端接收作为类对象。
服务器侧
public class newComment
{
public string ID;
public string Comment;
public string Email;
public string Name;
}
现在添加ASMX文件并创建webmethod，如下所示：
[WebMethod]
public string InsertMethod(newComment newComment)
{
// logic here
}
<强>客户端：
function test() {
var newComment = {};
newComment.Comment = "comment txt";
newComment.Email = "Email id";
newComment.Name = "your name";
newComment.ID = "32";
var jsonData = JSON.stringify({
newComment: newComment
});
$.ajax({
type: "POST",
url: "ajax_update.asmx/InsertMethod",
data: jsonData,
contentType: "application/json; charset=utf-8",
dataType: "json",
success: OnSuccess,
error: OnErrorCall
});
function OnSuccess(response){
var result=response.d;
console.log("success")
}
function OnErrorCall(response){
console.lof(response);
}
}