我正试图控制TPL Dataflow中的数据流。我有一个非常快的制作人和一个非常慢的消费者。 (我的真实代码更复杂,但是,这是一个非常好的模型,它可以重现问题。)
当我运行它时,代码开始饮用内存,就像它的样式一样 - 并且生产者的输出队列尽可能快地填满。我真正希望看到的是制作人停止运行一段时间,直到消费者有机会要求它。根据我对文档的阅读,这是应该发生的事情:也就是说,我认为生产者等到消费者有空间。
显然情况并非如此。如何修复它以使队列不会发疯?
using System;
using System.Linq;
using System.Threading.Tasks;
using System.Threading.Tasks.Dataflow;
using System.Threading;
namespace MemoryLeakTestCase
{
class Program
{
static void Main(string[] args)
{
var CreateData = new TransformManyBlock<int, string>(ignore =>
{
return Enumerable.Range(0, 1000 * 1000 * 1000).Select((s,i) => "Hello, World " + i);
});
var ParseFile = new TransformManyBlock<string, string>(fileContent =>
{
Thread.Sleep(1000);
return Enumerable.Range(0, 100).Select((sst, iii) => "Hello, " + iii);
}, new ExecutionDataflowBlockOptions() { BoundedCapacity = 1000 }
);
var EndOfTheLine = new ActionBlock<object>(f =>
{
});
var linkOptions = new DataflowLinkOptions { PropagateCompletion = true, };
CreateData.LinkTo(ParseFile, linkOptions);
ParseFile.LinkTo(EndOfTheLine, linkOptions);
Task t = new Task(() =>
{
while (true)
{
Console.WriteLine("CreateData: " + Report(CreateData));
Console.WriteLine("ParseData: " + Report(ParseFile));
Console.WriteLine("NullTarget: " + EndOfTheLine.InputCount );
Thread.Sleep(1000);
}
});
t.Start();
CreateData.SendAsync(0);
CreateData.Complete();
EndOfTheLine.Completion.Wait();
}
public static string Report<T, U>(TransformManyBlock<T, U> block)
{
return String.Format("INPUT: {0} OUTPUT: {1} ", block.InputCount.ToString().PadLeft(10, ' '), block.OutputCount.ToString().PadLeft(10, ' '));
}
}
}
答案 0 :(得分:4)
通常情况下,在这种情况下你要做的是设置BoundedCapacity
块的CreateData
。但是这不起作用,因为TransformManyBlock
在从单个BoundedCapacity
填充输出队列时似乎没有考虑IEnumerable
。
您可以做的是创建一个迭代集合的函数,并仅在目标可以接受时使用SendAsync()
发送更多数据:
/// <remarks>
/// If iterating data throws an exception, the target block is faulted
/// and the returned Task completes successfully.
///
/// Depending on the usage, this might or might not be what you want.
/// </remarks>
public static async Task SendAllAsync<T>(
this ITargetBlock<T> target, IEnumerable<T> data)
{
try
{
foreach (var item in data)
{
await target.SendAsync(item);
}
}
catch (Exception e)
{
target.Fault(e);
}
}
用法:
var data = Enumerable.Range(0, 1000 * 1000 * 1000).Select((s,i) => "Hello, World " + i);
await ParseFile.SendAllAsync(data);
ParseFile.Complete();
如果您仍希望CreateData
阻止其行为与原始代码相似,则可以在它们之间有两个有界BufferBlock
,SendAllAsync()
,然后使用Encapsulate()
使它们看起来像一个块:
/// <remarks>
/// boundedCapacity represents the capacity of the input queue
/// and the output queue separately, not their total.
/// </remarks>
public static IPropagatorBlock<TInput, TOutput>
CreateBoundedTransformManyBlock<TInput, TOutput>(
Func<TInput, IEnumerable<TOutput>> transform, int boundedCapacity)
{
var input = new BufferBlock<TInput>(
new DataflowBlockOptions { BoundedCapacity = boundedCapacity });
var output = new BufferBlock<TOutput>(
new DataflowBlockOptions { BoundedCapacity = boundedCapacity });
Task.Run(
async () =>
{
try
{
while (await input.OutputAvailableAsync())
{
var data = transform(await input.ReceiveAsync());
await output.SendAllAsync(data);
}
output.Complete();
}
catch (Exception e)
{
((IDataflowBlock)input).Fault(e);
((IDataflowBlock)output).Fault(e);
}
});
return DataflowBlock.Encapsulate(input, output);
}