Question

尝试使用基本指针功能显示用户输入的一些数字。但是，输入正常时显示错误。

#include <iostream>
using namespace std;

int main()
{
cout << "How many integers you wish to enter? ";
int InputNums = 0;
cin >> InputNums;

int* pNumbers = new int [InputNums]; // allocate requested integers
int* pCopy = pNumbers;

cout<<"Successfully allocated memory for "<<InputNums<< " integers"<<endl;
for(int Index = 0; Index < InputNums; ++Index)
{
cout << "Enter number "<< Index << ": ";
cin >> *(pNumbers++);
}

cout << "Displaying all numbers input: " << endl;

for(int Index = 0, int* pCopy = pNumbers; Index < InputNums; ++Index) 
    cout << *(pCopy++) << " ";

cout << endl;

// done with using the pointer? release memory
delete[] pNumbers;

return 0;
}

来自（int Index = 0，int * pCopy = pNumbers; Index＆lt; InputNums; ++ Index）的行的错误。

实际上来自教科书“在21天内教授c ++”的代码，没有任何改变。

请帮助，非常感谢。

Answer 1

你书中的例子很糟糕。它应该是这样的（代码也不好，但这里的代码应该是）：

#include <iostream>
using namespace std;

int main()
{
    cout << "How many integers you wish to enter? ";
    int InputNums = 0;
    cin >> InputNums;

    int* pNumbers = new int [InputNums]; // allocate requested integers
    int* pCopy = pNumbers;

    cout<<"Successfully allocated memory for "<<InputNums<< " integers"<<endl;
    for(int Index = 0; Index < InputNums; ++Index)
    {
        cout << "Enter number "<< Index << ": ";
        cin >> *(pCopy++); //use pCopy to 'walk' the array
    }

    cout << "Displaying all numbers input: " << endl;
    pCopy = pNumber; //reset pCopy
    for(int Index = 0; Index < InputNums; ++Index) 
        cout << *(pCopy++) << " ";

    cout << endl;

    // done with using the pointer? release memory
    delete[] pNumbers; //pNumbers must still point to the address returned in line 10

    return 0;
}

我想知道这本书的作者是谁。

Answer 2

将cin >> *(pNumbers++);更改为cin >> *(pCopy++);

将int* pCopy = pNumbers更改为*pCopy = pNumbers

这应该可以解决问题。然而，这个例子很丑陋。我建议你改变教科书。

得到错误C2062：使用教科书中的代码输入“int”意外

2 个答案: