Question

input = """
endless gibberish
some more stuff

color texture mytexture
    [640 480 1]
    'BE4C16FFBD4B15FFBD4B15FFBD4B15FFBD4B15FFBE4C16FFBE4C16FFBD4B15FFBD4B15FF'
    'BE4C16FFBE4C16FFBD4B15FFBC4A14FFBC4A14FFBC4A14FFBC4A14FFBC4A14FFBE4C16FF'
    'BF4C16FFBF4C16FFBE4B15FFBE4B15FFBC4913FFBC4913FFBC4913FFBB4812FFBC4913FF'
    'BC4A14FFBB4913FFBB4812FFBB4812FFBA4812FFBA4812FFBB4913FFBC4A16FFBB4915FF'
    'B84612FFB84612FFB94713FFB84612FFB64410FFB64410FFB64410FFB4420EFFB3410DFF'
    'FB03E0AFFB13F0BFB13F0BFFAE3C08FFAA3804FFAD3B07FFB03E0AFFB3410DFFB4420EFF'
    'B4400DFFB13D0AFFB23C0AFFB03C09FFB23E0BFFB5410EFFB74310FFB94512FFB84411FF'

color texture mytexture2
    [640 480 1]
    'BE4C16FFBD4B15FFBD4B15FFBD4B15FFBD4B15FFBE4C16FFBE4C16FFBD4B15FFBD4B15FF'
    'BE4C16FFBE4C16FFBD4B15FFBC4A14FFBC4A14FFBC4A14FFBC4A14FFBC4A14FFBE4C16FF'
    (... etc...)

"""

需要在带有“纹理”的行之后获取括号和二进制blob数据之间的内容，直到到达空行。有几个“纹理”段落。

这是我到目前为止所得到的：

p = re.compile(r'texture\s+(\S+)\s+\[(\d+\s+\d+\s+\d+)\]\s+(\'.+\')')
matches = p.findall(data)
    for match in matches:
         print match[0]
         print match[1]
         print match[2]
         print "---------------"

提供以下输出：

 mytexture
 640 480 1
 'BE4C16FFBD4B15FFBD4B15FFBD4B15FFBD4B15FFBE4C16FFBE4C16FFBD4B15FFBD4B15FF'
 ---------------
 mytexture2
 640 480 1
 'BE4C16FFBD4B15FFBD4B15FFBD4B15FFBD4B15FFBE4C16FFBE4C16FFBD4B15FFBD4B15FF'
 ---------------

我很确定re.MULTILINE应该用于获取整个 blob，但我不清楚如何抓取所有二进制行。我的问题基本上是：如何抓住多条线并知道何时“停止”（即：到达空行）。

Answer 1

re.MULTILINE会影响^和$锚点的含义。我认为你想要的是re.DOTALL，没有它.字符将永远不会与换行符匹配。

要将所有文字与下一个空行匹配，您可以使用(.*?)\n\s*\n之类的内容。这似乎可以满足您的需求？

p = re.compile(r'texture\s+(\S+)\s+\[(\d+\s+\d+\s+\d+)\]\s+(.*?)\n\s*\n', re.DOTALL)
matches = p.findall(input)
for match in matches:
    print match[0]
    print match[1]
    print match[2]
    print "---------------"

在示例文本中，这会产生：

mytexture
640 480 1
'BE4C16FFBD4B15FFBD4B15FFBD4B15FFBD4B15FFBE4C16FFBE4C16FFBD4B15FFBD4B15FF'
    'BE4C16FFBE4C16FFBD4B15FFBC4A14FFBC4A14FFBC4A14FFBC4A14FFBC4A14FFBE4C16FF'
    'BF4C16FFBF4C16FFBE4B15FFBE4B15FFBC4913FFBC4913FFBC4913FFBB4812FFBC4913FF'
    'BC4A14FFBB4913FFBB4812FFBB4812FFBA4812FFBA4812FFBB4913FFBC4A16FFBB4915FF'
    'B84612FFB84612FFB94713FFB84612FFB64410FFB64410FFB64410FFB4420EFFB3410DFF'
    'FB03E0AFFB13F0BFB13F0BFFAE3C08FFAA3804FFAD3B07FFB03E0AFFB3410DFFB4420EFF'
    'B4400DFFB13D0AFFB23C0AFFB03C09FFB23E0BFFB5410EFFB74310FFB94512FFB84411FF'
---------------
mytexture2
640 480 1
'BE4C16FFBD4B15FFBD4B15FFBD4B15FFBD4B15FFBE4C16FFBE4C16FFBD4B15FFBD4B15FF'
    'BE4C16FFBE4C16FFBD4B15FFBC4A14FFBC4A14FFBC4A14FFBC4A14FFBC4A14FFBE4C16FF'
    (... etc...)
---------------

Answer 2

你是现场的，只是没有实际实现它;）

import re

input = """
endless gibberish
some more stuff

texture mytexture
    '01AB01AB01AB01BA'
    '01AB01AB01AB01BA'
    '01AB01AB01AB01BA'
    '01AB01AB01AB01BA'

"""

matches = re.findall(r'01AB01AB01AB01BA', input, re.M)
print matches

Python多线正则表达式

2 个答案: