Question

我有一个复制变量并将其分发给不同对象的方法。我想验证正在发送的对象确实是不同的对象，而不是指向同一对象的不同指针。

我的测试目前看起来像这样：

it 'uses different objects when false' do
  object1 = SomeClass.new
  object2 = SomeClass.new
  data = "something"

  MasterClass.register(object1)
  MasterClass.register(object2)

  #Not correct:
  expect(object1).to_not receive(:get_data).with(data) 
  expect(object2).to_not receive(:get_data).with(data)

  #False is supposed to mean 
  # "create new objects for each call to get_data for the SomeClass"
  MasterClass.distribute_data(data, false) 
end

我知道我可以使用a.equal?(b)测试对象属性的相等性，但是当我想测试的对象是rspec mock中with方法中的参数时，我怎么能这样做？ / p>

Answer 1

这应该有效，向receive匹配器添加一个块，并使用匹配器be：

describe "Example" do
  it "should find something, but not using the original variable" do
    text = "Hi!"
    original = "!"
    copied = original.clone
    expect( text ).to receive(:include?) { |x| x.should_not be original; true }
    text.include?( copied ).should be_true
  end
end

您的等效内容可能如下所示：

expect(object1).to receive(:get_data) do |d| 
   d.should_not be data
   d.should == data
end

Answer 2

这是一个坚持使用“expect”语法的版本：

it 'uses different objects when false' do
  object1 = SomeClass.new
  object2 = SomeClass.new
  data = "something"

  MasterClass.register(object1)
  MasterClass.register(object2)

  arg1 = nil
  expect(object1).to receive(:get_data) {|arg| arg1 = arg}
  expect(object2).to receive(:get_data) {|arg| expect(arg).to_not equal(arg1)}

  #False is supposed to mean 
  # "create new objects for each call to get_data for the SomeClass"
  MasterClass.distribute_data(data, false) 
end

Rspec模拟，验证收到的对象是不一样的

2 个答案: