我有多个外键关联的模型。我可以在一对一的基础上使用django rest框架单独导出它们,我也可以导出多个嵌套的。但是我希望能够将它们基本上“连接”到一个json / xml导出中。
以下示例中的模型由jobdtl_id上的一对一外键连接。我有一些它是一对一的但是我希望当我知道如何获得一个可以链接2个单独模型的视图时我可以弄明白 -
这是一个通过点击像
这样的网址,希望json看起来像什么的例子 http://localhost/job/4/
{
"job": {
"-id": "9878",
"-name": "This is the job",
"-master": "blahserver",
"-dbversion": "234",
"-xmlversion": "1",
"jobmst": {
"jobmst_id": "9878",
"jobmst_type": "2",
"jobmst_prntid": "234",
"jobmst_active": "Y",
"jobmst_name": "This is the job",
"jobmst_owner": "Owner",
"jobdtl_id": "9878",
"jobmst_lstchgtm": {
"-date": "Y",
"#text": "2013-10-23 09:22:08.0"
},
"jobmst_prntname": "Parent",
"jobmst_alias": "9878"
},
"jobdtl": {
"jobdtl_id": "9878",
"jobdtl_cmd": "blah.exe",
"jobdtl_failalarm": "NULL",
"nodmst_id": "NULL",
"nodlstmst_id": "NULL",
"jobdtl_inhevent": "Y",
"jobdtl_inhoptions": "Y",
"jobdtl_inhagent": "Y",
"jobdtl_inhrepeat": "Y",
"jobdtl_inhtime": "Y",
"jobdtl_timewin": "NULL",
"jobdtl_saveoutput": "Y",
"jobdtl_outputname": "NULL",
"jobdtl_trackmethod": "1",
"jobdtl_trackcmd": "NULL",
"jobdtl_deplogic": "1",
"jobdtl_rerun": "NULL",
"jobdtl_params": "--blah --ok"
},
"jobdep": [
{
"jobdep_id": "79670",
"jobmst_id": "9878",
"jobdep_type": "1",
"jobdep_jobmst": "another job",
"varmst_id": "NULL"
},
{
"-num": "2",
"jobdep_id": "83783",
"jobmst_id": "9878",
"jobdep_type": "1",
"jobdep_jobmst": "and another",
"varmst_id": "NULL"
}
],
"trgjob": [
{
"trgjob_id": "22286",
"trgmst_id": "23455",
"jobmst_id": "9878"
},
{
"-num": "2",
"trgjob_id": "28980",
"trgmst_id": "23521",
"jobmst_id": "9878"
},
{
"-num": "3",
"trgjob_id": "28981",
"trgmst_id": "9237",
"jobmst_id": "9878"
}
]
}
}
模型基本上就是这样 -
class Jobdtl(models.Model):
jobdtl_id = models.IntegerField(primary_key=True)
jobdtl_cmd = models.TextField(blank=True)
....
jobdtl_duration = models.IntegerField(blank=True, null=True)
class Meta:
managed = False
db_table = 'jobdtl'
class Jobmst(models.Model):
jobmst_id = models.IntegerField(primary_key=True)
jobmst_type = models.SmallIntegerField()
....
jobdtl_id = models.ForeignKey('Jobdtl', db_column='jobdtl_id', related_name='mstdtl', blank=True, null=True)
def __unicode__(self):
return self.jobmst_name
class Meta:
managed = False
db_table = 'jobmst'
结束告诫我正在将json转换为XML如何查找现有的遗留应用程序,就像这样 -
<?xml version="1.0"?>
<job id="9878" name="This is the job" master="blahserver" dbversion="532" xmlversion="1">
<jobmst>
<jobmst_id>9878</jobmst_id>
<jobmst_type>2</jobmst_type>
<jobmst_prntid>234</jobmst_prntid>
<jobmst_active>Y</jobmst_active>
<jobmst_name>This is the job</jobmst_name>
<jobmst_owner>Owner</jobmst_owner>
<jobdtl_id>9878</jobdtl_id>
<jobmst_lstchgtm date="Y">2013-10-23 09:22:08.0</jobmst_lstchgtm>
<jobmst_prntname>Parent</jobmst_prntname>
<jobmst_alias>9878</jobmst_alias>
</jobmst>
<jobdtl>
<jobdtl_id>9878</jobdtl_id>
<jobdtl_cmd>blah.exe</jobdtl_cmd>
<jobdtl_failalarm>NULL</jobdtl_failalarm>
<nodmst_id>NULL</nodmst_id>
<nodlstmst_id>NULL</nodlstmst_id>
<jobdtl_inhevent>Y</jobdtl_inhevent>
<jobdtl_inhoptions>Y</jobdtl_inhoptions>
<jobdtl_inhagent>Y</jobdtl_inhagent>
<jobdtl_inhrepeat>Y</jobdtl_inhrepeat>
<jobdtl_inhtime>Y</jobdtl_inhtime>
<jobdtl_timewin>NULL</jobdtl_timewin>
<jobdtl_saveoutput>Y</jobdtl_saveoutput>
<jobdtl_outputname>NULL</jobdtl_outputname>
<jobdtl_trackmethod>1</jobdtl_trackmethod>
<jobdtl_trackcmd>NULL</jobdtl_trackcmd>
<jobdtl_deplogic>1</jobdtl_deplogic>
<jobdtl_rerun>NULL</jobdtl_rerun>
<jobdtl_params>--blah --ok</jobdtl_params>
</jobdtl>
<jobdep>
<jobdep_id>79670</jobdep_id>
<jobmst_id>9878</jobmst_id>
<jobdep_type>1</jobdep_type>
<jobdep_jobmst>another job</jobdep_jobmst>
<varmst_id>NULL</varmst_id>
</jobdep>
<jobdep num="2">
<jobdep_id>83783</jobdep_id>
<jobmst_id>9878</jobmst_id>
<jobdep_type>1</jobdep_type>
<jobdep_jobmst>and another</jobdep_jobmst>
<varmst_id>NULL</varmst_id>
</jobdep>
<trgjob>
<trgjob_id>22286</trgjob_id>
<trgmst_id>23455</trgmst_id>
<jobmst_id>9878</jobmst_id>
</trgjob>
<trgjob num="2">
<trgjob_id>28980</trgjob_id>
<trgmst_id>23521</trgmst_id>
<jobmst_id>9878</jobmst_id>
</trgjob>
<trgjob num="3">
<trgjob_id>28981</trgjob_id>
<trgmst_id>9237</trgmst_id>
<jobmst_id>9878</jobmst_id>
</trgjob>
</job>
答案 0 :(得分:0)
class MSTSerializer(serializers.HyperlinkedModelSerializer):
jobdtl_id = DTLSerializer()
class Meta:
model = Jobmst
fields = ('id', 'url', 'jobdtl_id'...)
class DTLSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = Jobdtl
fields = ('id', 'url', ...)
将导致更正确的数据结构
{
"jobmst_id": 4,
"jobmst_type": 1,
"jobdtl_id": {
"jobdtl_id": 4,
"jobdtl_cmd": null,
"jobdtl_duration": 1379
},
}
答案 1 :(得分:0)
我通过在views.py
中执行以下操作找到了解决方案...
@csrf_exempt
def tesxml_test(request, pk):
"""
Retrieve, update or delete a code snippet.
"""
try:
mst = Jobmst.objects.using('database1').get(jobmst_id=pk)
dtl = Jobdtl.objects.using('database1').get(jobdtl_id=pk)
dep = Jobdep.objects.using('database2').filter(jobmst_id=pk).order_by('jobdep_id')
trg = Trgjob.objects.using('database1').filter(jobmst_id=pk).order_by('trgjob_order')
except Jobmst.DoesNotExist:
return HttpResponse(status=404)
if request.method == 'GET':
#Get String Results of 4 queries
jobmststring = JobmstSerializer(mst)
jobdtlstring = JobdtlSerializer(dtl)
jobdepstring = JobdepSerializer(dep)
trgjobstring = TrgjobSerializer(trg)
#Get serialized Results of 4 queries
jobmst_serialized = {'jobmst': jobmststring.data}
jobdtl_serialized = {'jobdtl': jobdtlstring.data}
jobdep_serialized = {'jobdep': jobdepstring.data}
trgjob_serialized = {'trgjob': trgjobstring.data}
jobgroup = jobmst_serialized, jobdtl_serialized, jobdep_serialized, trgjob_serialized,
jobgroupresponse = TESXMLResponse(jobgroup)
return jobgroupresponse
...
它并不完美,但它让我进入我的问题的下一步,即自定义渲染器以获取根域中的数据,我有另外的SO问题:)