我有一个包含3500行的长文本文件。该文件的内容如下:
Iteration 26
WSSR : 2.16978 delta(WSSR)/WSSR : -5.96505e-05
delta(WSSR) : -0.000129428 limit for stopping : 1e-05
lambda : 1.92367e-12
resultant parameter values
A = 0.152297
B = 22009.9
/
Iteration 27
WSSR : 2.16978 delta(WSSR)/WSSR : -6.95237e-07
delta(WSSR) : -1.50851e-06 limit for stopping : 1e-05
lambda : 1.92367e-13
resultant parameter values
A = 0.152268
B = 22018.5
After 27 iterations the fit converged.
final sum of squares of residuals : 2.16978
rel. change during last iteration : -6.95237e-07
degrees of freedom (FIT_NDF) : 15996
rms of residuals (FIT_STDFIT) = sqrt(WSSR/ndf) : 0.0116467
variance of residuals (reduced chisquare) = WSSR/ndf : 0.000135645
Final set of parameters Asymptotic Standard Error
======================= ==========================
A = 0.152268 +/- 0.0003536 (0.2322%)
B = 22018.5 +/- 73.18 (0.3324%)
correlation matrix of the fit parameters:
A B
A 1.000
B -0.712 1.000
Max. number of data points scaled up to: 3072
Max. number of data points scaled up to: 4608
Max. number of data points scaled up to: 6912
Max. number of data points scaled up to: 10368
Max. number of data points scaled up to: 15552
Max. number of data points scaled up to: 23328
Iteration 0
WSSR : 92.7915 delta(WSSR)/WSSR : 0
delta(WSSR) : 0 limit for stopping : 1e-05
lambda : 0.000192367
initial set of free parameter values
C = 1
D = 1
***/
Iteration 1
WSSR : 92.7561 delta(WSSR)/WSSR : -0.000382419
delta(WSSR) : -0.0354717 limit for stopping : 1e-05
lambda : 0.0192367
resultant parameter values
C = 1.09786
D = 1.4932
/
Iteration 2
WSSR : 91.9873 delta(WSSR)/WSSR : -0.00835736
delta(WSSR) : -0.768771 limit for stopping : 1e-05
lambda : 0.00192367
我想从整个文本文件中的最终参数集渐近标准错误开始选择6条特定行。这组行不会在文本文件中以周期性方式出现。有时它发生在10行或30行之后。
我能想到grep命令。但我有经验使用它只选择具有特定单词的特定行。像这样的东西
grep "Final set of parameters"
但是,是否需要添加任何选项以实现我的需求?
我怎么能这样做?
答案 0 :(得分:2)
grep -A6 'Final set of parameters' file
给出:
kent$ grep -A6 'Final set of parameters' f
Final set of parameters Asymptotic Standard Error
======================= ==========================
A = 0.152268 +/- 0.0003536 (0.2322%)
B = 22018.5 +/- 73.18 (0.3324%)
答案 1 :(得分:2)
您也可以使用awk
awk '/Final set of parameters/ {f=6} f && f-- '
Final set of parameters Asymptotic Standard Error
======================= ==========================
A = 0.152268 +/- 0.0003536 (0.2322%)
B = 22018.5 +/- 73.18 (0.3324%)