Question

当我需要提取参数值的URL字符串中有URIError: malformed URI sequence?符号%时，60% - Completed以下代码错误消失了，例如http://some-external-server.com/info?progress=60%%20-%20Completed

   <SCRIPT type="text/javascript">
            function getParameterByName(name) {
                name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
                var regex = new RegExp("[\\?&]" + name + "=([^&#]*)"),
                results = regex.exec(location.search);
                return results == null ? "" : decodeURIComponent(results[1].replace(/\+/g, " "));
            }
    </SCRIPT>

我无法控制服务器，需要在html页面中处理输出。

Answer 1

我认为您需要将百分号URI编码为'％25'

http://some-external-server.com/info?progress=60%25%20-%20Completed

[编辑]

我想你可以这样做：

var str = "60%%20-%20completed";
var uri_encoded = str.replace(/%([^\d].)/, "%25$1");
console.log(str); // "60%25%20-%20completed"
var decoded = decodeURIComponent(uri_encoded);
console.log(decoded); // "60% - completed"

URIError：错误的URI序列？

1 个答案: