Hive UDF返回类型数组<int> </int>

Question

我正在编写一个基于split（）GenericUDF的Hive UDF。我的函数split_int（）接受字符串参数split_int(str,regex)，例如split_int("1,2,3",",")。我想返回array<int>，而是获得array<string>

代码：

public class SplitIntUDFSplit extends GenericUDF {
     private ObjectInspectorConverters.Converter[] converters;

     @Override
     public ObjectInspector initialize(ObjectInspector[] arguments) throws UDFArgumentException {
           if (arguments.length != 2) {
              throw new UDFArgumentLengthException(
              "The function SPLIT(s, regexp) takes exactly 2 arguments.");
           }

           converters = new ObjectInspectorConverters.Converter[arguments.length];
           for (int i = 0; i < arguments.length; i++) {
           converters[i] = ObjectInspectorConverters.getConverter(arguments[i],
                PrimitiveObjectInspectorFactory.writableStringObjectInspector);
           }
           return ObjectInspectorFactory.
            getStandardListObjectInspector(PrimitiveObjectInspectorFactory.writableIntObjectInspector);
     }

     @Override
     public Object evaluate(DeferredObject[] arguments) throws HiveException {
         assert (arguments.length == 2);

           if (arguments[0].get() == null || arguments[1].get() == null) {
               return null;
           }

           Text s = (Text) converters[0].convert(arguments[0].get());
           Text regex = (Text) converters[1].convert(arguments[1].get());

           ArrayList<IntWritable> result = new ArrayList<IntWritable>();


           for (String str : s.toString().split(regex.toString())) {
                  result.add(new IntWritable(Integer.parseInt(str)));
           }
           return result;
     }

如何让udf返回array<int>？