<img onClick="return chkall()" id="btnchkall" name="btnchkall" class="submit_button" value="Check All" src="images/check_all.jpg">
<img onClick="return unchkall()" id="btnunchkall" name="btnunchkall" class="submit_button" value="Uncheck All" src="images/uncheck_all.jpg">
function chkall() {
// var status=$('#btnchkall').val();
$('input[name="checkbox[]"]').attr('checked', true);
$('#btnchkall').css('display','none');
$('#btnunchkall').css('display','block');
//$('#btnchkall').attr('alt','uncheckall');
// $('#btnchkall').attr('value','un check');
}
function unchkall(){
$('input[name="checkbox[]"]').attr('checked', false);
$('#btnchkall').css('display','block');
$('#btnunchkall').css('display','none');
}
<input type="checkbox" name="checkbox[]" class="chech_box" value="<?php echo $value->intstatusid;?>">
当页面刷新时,它正在工作一次....之后就无法工作......
答案 0 :(得分:0)
试试这个..
function chkall() {
$('.chech_box').attr('checked', true);
}
function unchkall(){
$('.chech_box').attr('checked', false);
}
答案 1 :(得分:0)
如果你使用jQuery 1.6+,你应该使用新的.prop()函数:
$('。submit_button')。prop('checked',true);
$('。submit_button')。prop('checked',false);
答案 2 :(得分:0)
#Display seleted news in text field
if not True in user_selection:
text_box.insert(0.0, "you need to select at least one news. ")
else:
if user_selection[0]:
text_box.insert(END, "you select Education_Family. ")
if user_selection[1]:
text_box.insert(END, "you select Politics. ")
if user_selection[2]:
text_box.insert(END, "you select Science_Environment. ")
if user_selection[3]:
text_box.insert(END, "you select entertainment_Arts. ")