Question

我正在尝试根据个人用户ID从数据库中的表中检索数据。我一直在说：

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /xampp/... on line 50

和

 Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /xampp/... on line 52

这是我的代码：

37.    $sql6 = mysql_query("SELECT * FROM replies WHERE thread_id = $thread_id");
38.    $numRows = mysql_num_rows($sql6);
39.    $replies = '';
40.    if ($numRows < 1) {
41.        $replies =  "There are no replies yet, you can make the first!";
42.    } else {
43.       while ($rows = mysql_fetch_array($sql6)) {
44.            $reply_content = $rows[5];
45.            $reply_username = $rows[7];
46.            $reply_date = $rows[8];
47.            $reply_author_id = $rows[4];
48.            
49.            $sql9 = mysql_query("SELECT * FROM users WHERE id = $reply_author_id");
50.            $numRows = mysql_num_rows($sql9); 
51.            if ($numRows < 1) {
52.                while ($rows = mysql_fetch_array($sql9)) {
53.                    $reply_user_fn = $rows['first_name'];
54.                    $reply_user_ln = $rows['last_name'];
55.                    $reply_user_id = $rows['id'];
56.                    $reply_user_pp = $rows['profile_pic'];
57.                    $reply_user_lvl = $rows['user_level'];
58.                    $reply_user_threads = $rows['threads'];
59.                    $reply_user_email = $rows['email'];
60.                        
61.                        
62.                    }
63.                }
64.            }
65.        }

我也放或死（mysql_error（））;在我所有的SQL查询上，我不断得到：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'bla bla bla' at line 1

我页面上的第1行是：

<?php include_once('config.php'); ?> //Connect to database

所以这没有任何意义。请帮帮我。

由于

Answer 1

尝试交换此（添加''）：

$sql9 = mysql_query("SELECT * FROM users WHERE id = '$reply_author_id'");

Answer 2

我建议，尝试连接查询。试试这个。

$sql9 = mysql_query("SELECT * FROM users WHERE id = ".$reply_author_id);

我总是使用这种格式。我希望这可以帮到你。

我的mysql语法有错误

2 个答案: