我是Symfony框架的新手,并使用教程http://blog.tankist.de/blog/2013/07/17/oauth2-explained-part-2-setting-up-oauth2-with-symfony2-using-fosoauthserverbundle/获取错误:
ClassNotFoundException: Attempted to load class "UserRepository" from namespace "Acme\DemoBundle\Repository" in C:\xampp\htdocs\*****\vendor\doctrine\orm\lib\Doctrine\ORM\Repository\DefaultRepositoryFactory.php line 75. Do you need to "use" it from another namespace?
我认为该代码可能会导致此错误:
<!-- src/Acme/DemoBundle/Resources/config/services.xml -->
<parameters>
<parameter key="platform.entity.user.class">Acme\DemoBundle\Entity\User</parameter>
<parameter key="platform.user.provider.class">Acme\DemoBundle\Provider\UserProvider</parameter>
</parameters>
<services>
<service id="platform.user.manager" class="Doctrine\ORM\EntityManager"
factory-service="doctrine" factory-method="getManagerForClass">
<argument>%platform.entity.user.class%</argument>
</service>
<service id="platform.user.repository"
class="Acme\DemoBundle\Repository\UserRepository"
factory-service="platform.user.manager" factory-method="getRepository">
<argument>%platform.entity.user.class%</argument>
</service>
<service id="platform.user.provider" class="%platform.user.provider.class%">
<argument type="service" id="platform.user.repository" />
</service>
</services>
OR
<?php
// src/Acme/DemoBundle/Provider/UserProvider.php
namespace Acme\DemoBundle\Provider;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Core\Exception\UsernameNotFoundException;
use Symfony\Component\Security\Core\Exception\UnsupportedUserException;
use Doctrine\Common\Persistence\ObjectRepository;
use Doctrine\ORM\NoResultException;
class UserProvider implements UserProviderInterface
{
protected $userRepository;
public function __construct(ObjectRepository $userRepository){
$this->userRepository = $userRepository;
}
public function loadUserByUsername($username)
{
$q = $this->userRepository
->createQueryBuilder('u')
->where('u.username = :username OR u.email = :email')
->setParameter('username', $username)
->setParameter('email', $username)
->getQuery();
try {
$user = $q->getSingleResult();
} catch (NoResultException $e) {
$message = sprintf(
'Unable to find an active admin AcmeDemoBundle:User object identified by "%s".',
$username
);
throw new UsernameNotFoundException($message, 0, $e);
}
return $user;
}
public function refreshUser(UserInterface $user)
{
$class = get_class($user);
if (!$this->supportsClass($class)) {
throw new UnsupportedUserException(
sprintf(
'Instances of "%s" are not supported.',
$class
)
);
}
return $this->userRepository->find($user->getId());
}
public function supportsClass($class)
{
return $this->userRepository->getClassName() === $class
|| is_subclass_of($class, $this->userRepository->getClassName());
}
}
但我无法理解......
答案 0 :(得分:4)
我遇到了同样的问题,这就是我所做的。
在实体文件夹
中创建名为 UserRepository.PHP 的文件在里面,把这段代码
命名空间Login \ LoginBundle \ Entity;
use Doctrine\ORM\EntityRepository;
/**
* UserRepository
*
* This class was generated by the Doctrine ORM. Add your own custom
* repository methods below.
*/
class UserRepository extends EntityRepository
{
}
使用正确的命名空间,包名称,类名等。这对我有用,希望它也适合你。
答案 1 :(得分:3)
正确答案如下:
在src / Acme / DemoBundle /
下创建一个新文件夹Repository使用以下代码创建新文件UserRepository.php。
<?php
namespace Acme\DemoBundle\Repository;
use Doctrine\ORM\EntityRepository;
/**
* UserRepository
*
* This class was generated by the Doctrine ORM. Add your own custom
* repository methods below.
*/
class UserRepository extends EntityRepository
{
}
这是纠正错误的原因,如果您发现错误,则表明未在&#34; Acme \ DemoBundle \ Repository&#34;中找到类UserRepository。因此,它只是在该目录中创建该类。
答案 2 :(得分:1)
在项目根目录的命令行中尝试:
$ php app/console doctrine:generate:entities YourAppBundle
这将有助于使实体处于正确的顺序并可能解决问题。它对我有用。 :)