Question

我有两张桌子：

表1）courses_cat（这个有＆＃34;标题＆＃34;字段）
表2）courses（这个有一个＆＃34;父＆＃34;字段，我想用到＆＃34; group＆＃34;，这个＆＃34; parent＆＃34;是相等的到＆＃34;标题＆＃34;

所以我需要以图形方式＆＃34;＆＃34;表1中表2的内容。

这是我的代码（两个表分开）：

<?php
$query = $db->prepare('SELECT title, body, showeb, datapost FROM courses_cat WHERE showeb="si"');
$query->execute();
$query->store_result();
$query->bind_result($title, $body, $showeb, $datapost);
while ($query->fetch())

echo " <div class='pblock'><h2>$title</h2><pre>$body</pre></div> "; 
?>

<?php
$query2 = $db->prepare('SELECT parent, title, body, showeb, datapost FROM courses WHERE showeb="si"');
 $query2->execute();
 $query2->store_result();
 $query2->bind_result($parent, $title, $body, $showeb, $datapost);
 while ($query2->fetch())

 echo " <div id='courseblock'><a href='#'><span class='top'>$title</span><span class='content'>$shortbody</span></a></div>"; 
?>

Answer 1

我不确定我100％理解最终结果应该是什么，但我相信你可以将你的两个查询合并为一个;正确地循环这可能会解决您的问题：

SELECT cat.title as CatTitle, cat.body as CatBody, courses.title as CourseTitle, courses.body as CourseBody -- and any other fields you need like that
FROM courses_cat cat, courses
WHERE cat.parent = courses.title
GROUP BY cat.title

Answer 2

我尝试使用Digital Chris发布的代码，它的工作原理（部分），为了更好地解释，下面的代码（见下面编辑过的代码）“分组确定类别并把项目放在里面”但我需要得到更多的一个课程（div“courseblock”）到每个类别（div“pblock”），这个代码只打印一个...（我认为它“打破了循环”，可能需要将“课程”的数据加入到他们的“类别“）

在这个链接可以看到我的意思的图形示例：
http://liberartestudio.com/download/aaa.jpg
（类别块是那些白人，课程是红色的）
这里是页面的链接：
http://lvdsys.liberartestudio.com/services_courses.php

 <?php
 $query = $db->prepare(' 
SELECT courses_cat.title AS CatTitle, courses_cat.body AS CatBody, courses_cat.datapost AS CatData, courses.parent, courses.title AS CourseTitle, courses.shortbody AS CourseShortbody, courses.datapost AS CourseData 
FROM courses_cat, courses 
WHERE courses_cat.title = courses.parent 
GROUP BY parent 
ORDER BY CatData AND CourseData
');
$query->execute();
$query->store_result();
$query->bind_result($CatTitle, $CatBody, $CatData, $parent, $CourseTitle, $CourseShortbody, $CourseData);
while ($query->fetch())
echo "
<div class='pblock'>
<h2>$CatTitle</h2><pre>$CatBody</pre>
<div id='courseblock'><a href='#'><span class='top'>$CourseTitle</span><span class='content'>$CourseShortbody</span></a>
</div>
</div>
"; ?>

Answer 3

这里是我需要的工作代码（简单版本）...

<?php
$cat = mysqli_query($db,"SELECT title AS catTitle, body AS catBody FROM courses_cat");
$result = mysqli_query($db,"SELECT parent, title, shortbody FROM courses");

//array x categories
$category = array(); while ($row = mysqli_fetch_assoc($cat)) {$category[] = $row;}

//array x courses
$course = array(); while ($row = mysqli_fetch_assoc($result)) {$course[] = $row;}

// here my divs
$cat_div="";
foreach ($category as $row) {  
$cat_div = $row['catTitle'];
echo "<div class='pblock'>";
echo "<h2>".$row['catTitle']."</h2><pre>".$row['catBody']."</pre>";

foreach ($course as $row) {
if ($cat_div == $row['parent']) {
echo "<div id='courseblock'><a href='#'><span class='top'>".$row['title']."</span><span> class='content'>".$row['shortbody']."</span></a></div>";}}
echo "</div>";}

$cat->free_result();
$result->free_result();
mysqli_close($db);
?>

Mysql，如何组“从图形上”查询来自2个不同的表

3 个答案: