XML - DTD，两个元素相同的属性

Question

为什么以下代码不正确？ XMLspy在元素employee

中发现错误

<!ELEMENT personnel (contractor*,employee*,partner*)+ >
<!ELEMENT contractor (info)>
<!ELEMENT employee(info)>
<!ATTLIST info lname CDATA #REQUIRED fname CDATA #REQUIRED hiredate CDATA #REQUIRED firedate CDATA #REQUIRED>

Answer 1

employee后需要一个空格。

info元素也未定义。

如果你要做的是获取contractor和employee上的属性，那么就这样做了：

<!ELEMENT personnel (contractor*, employee*, partner*)+ >
<!ELEMENT contractor EMPTY>
<!ELEMENT employee EMPTY>
<!ATTLIST contractor lname CDATA #REQUIRED fname CDATA #REQUIRED hiredate CDATA #REQUIRED firedate CDATA #REQUIRED>
<!ATTLIST employee lname CDATA #REQUIRED fname CDATA #REQUIRED hiredate CDATA #REQUIRED firedate CDATA #REQUIRED>

根据上述DTD，这是有效的：

<personnel>
  <employee lname="Foo" fname="Bar" firedate="1" hiredate="2"/>
  <contractor lname="Foo" fname="Bar" firedate="1" hiredate="2"/>
</personnel>

或者你可以像这样分享属性声明：

<!ENTITY % shared "lname CDATA #REQUIRED fname CDATA #REQUIRED hiredate CDATA #REQUIRED firedate CDATA #REQUIRED">
<!ELEMENT personnel (contractor*, employee*, partner*)+ >
<!ELEMENT contractor EMPTY>
<!ELEMENT employee EMPTY>
<!ATTLIST contractor %shared;>
<!ATTLIST employee %shared;>

这样，如果您需要更改属性列表，则contractor和employee都会更改。