[[4, 17, 28, 38, 43, 58, 69, 77, 83], [4, 12, 24, 35, 48, 55, 62, 73, 87], [11,
15, 22, 36, 46, 60, 67, 80, 84]]
如何将其转换为:
[4, 17, 28, 38, 43, 58, 69, 77, 83, 4, 12, 24, 35, 48, 55, 62, 73, 87, 11,
15, 22, 36, 46, 60, 67, 80, 84]
有一种简单的方法吗?
答案 0 :(得分:2)
ArrayUtils.addAll(array1,array2)
答案 1 :(得分:1)
您可以创建一个新数组并使用for循环手动填充,如下所示:
int[][] numbers = {{4, 5, 6},{3, 1, 10}, {4, 2, 9}};
ArrayList<Integer> numbers1Dim = new ArrayList<Integer>();
for (int i = 0; i < numbers.length; i++)
{
for (int x = 0; x < numbers[i].length; x++)
{
numbers1Dim.add(numbers[i][x]);
}
}
答案 2 :(得分:1)
这样做
Integer td[][]= {{4, 17, 28, 38, 43, 58, 69, 77, 83}, {4, 12, 24, 35, 48, 55, 62, 73, 87}, {11,15, 22, 36, 46, 60, 67, 80, 84}};
List<Integer> singleDArray = new ArrayList<Integer>();
for (Integer[] array :td) {
singleDArray.addAll(Arrays.asList(array));
}
Integer[] sd = singleDArray.toArray(new Integer[singleDArray.size()]);
答案 3 :(得分:0)
我会使用嵌套的for循环:
Integer[][] array = <your array>;
List resultList = new ArrayList();
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array[i].length; j++) {
resultList.add(array[i][j]);
}
}
Integer[] resultArrayList = resultList.toArray(new Integer[resultList.size()]);
System.out.println(resultArrayList);
}