Question

我有一个列表列表，我想从列表列表中选择重复的元素并打印出来。列表清单如下所示，

a = [[0, 1, 2, 3], [4, 5, 6, 375],  [142, 132, 143, 144], [172, 173, 174, 297],  [181, 182, 183, 339], [205, 144, 206, 207], [295, 108, 296, 297]]

我尝试使用以下脚本

for i in range(len(a)):
   for j in range(1, len(a)):
      for m in range(3):
         for n in range(3):
            if a[i][m] == a[j][n]:
                print a[j][n]

但它只是打印

任何人都想尝试并帮助我？

Answer 1

此代码应该有效：

a = [[0, 1, 2, 3], [4, 5, 6, 375],  [142, 132, 143, 144], [172, 173, 174, 297],  [181, 182, 183, 339], [205, 144, 206, 207], [295, 108, 296, 297]]

master = [] #this will be a list with every individual element
for array in a: #take every sub-list
     for element in array: #do this for every element in the sub-list
         if not(element in master): #check that it is not a duplicate
             master.append(element) #add the element to your master list

for element in master:
    print(element)

Answer 2

#!/usr/local/bin/python2.7
a = [[0, 1, 2, 3], [4, 5, 6, 375],  [142, 132, 143, 144], [172, 173, 174, 297],  [181, 182, 183, 339], [205, 144, 206, 207], [295, 108, 296, 297]]
a2 = []
for list1 in a:
  a2.extend(list1)
print a2
a2.sort()
for i, n in enumerate(a2):
  if i < len(a2)-2 and n == a2[i+1]:
    print (n)

我很确定还有其他更有效，更简单的解决方案。等待其他帖子

如何在列表列表中查找重复元素？

2 个答案: