Question

我的页面上有一个PHP表单，如下所示 -

<?php
if(isset($_POST['email'])) {

    // EDIT THE 2 LINES BELOW AS REQUIRED
    $email_to = "someone@somewhere.com";
    $email_subject = "subject";


    function died($error) {
        // your error code can go here
        echo "We are very sorry, but there were error(s) found with the form you submitted. ";
        echo "These errors appear below.<br /><br />";
        echo $error."<br /><br />";
        echo "Please go back and fix these errors.<br /><br />";
        die();
    }

    // validation expected data exists
    if(!isset($_POST['first_name']) ||
        !isset($_POST['last_name']) ||
        !isset($_POST['email']) ||
        !isset($_POST['telephone']) ||
        !isset($_POST['comments'])) {
        died('We are sorry, but there appears to be a problem with the form you submitted.');       
    }

    $first_name = $_POST['first_name']; // required
    $last_name = $_POST['last_name']; // required
    $email_from = $_POST['email']; // required
    $telephone = $_POST['telephone']; // not required
    $comments = $_POST['comments']; // required

    $error_message = "";
    $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';
  if(!preg_match($email_exp,$email_from)) {
    $error_message .= 'The Email Address you entered does not appear to be valid.<br />';
  }
    $string_exp = "/^[A-Za-z .'-]+$/";
  if(!preg_match($string_exp,$first_name)) {
    $error_message .= 'The First Name you entered does not appear to be valid.<br />';
  }
  if(!preg_match($string_exp,$last_name)) {
    $error_message .= 'The Last Name you entered does not appear to be valid.<br />';
  }
  if(strlen($comments) < 2) {
    $error_message .= 'The Comments you entered do not appear to be valid.<br />';
  }
  if(strlen($error_message) > 0) {
    died($error_message);
  }
    $email_message = "Form details below.\n\n";

    function clean_string($string) {
      $bad = array("content-type","bcc:","to:","cc:","href");
      return str_replace($bad,"",$string);
    }

    $email_message .= "First Name: ".clean_string($first_name)."\n";
    $email_message .= "Last Name: ".clean_string($last_name)."\n";
    $email_message .= "Email: ".clean_string($email_from)."\n";
    $email_message .= "Telephone: ".clean_string($telephone)."\n";
    $email_message .= "Comments: ".clean_string($comments)."\n";


// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_from."\r\n" .
'X-Mailer: PHP/' . phpversion();
@mail($email_to, $email_subject, $email_message, $headers);  
?>

<!-- include your own success html here -->

Thank you for contacting us. We will be in touch with you very soon.

<?php
}
?>

我希望在单击提交按钮时，成功行将作为页面上的对话框而不是新页面出现。不幸的是，如果无法做到这一点，那么有没有办法对单击提交按钮后出现的文本（成功线）进行样式化？在此先感谢，请帮助。

Answer 1

是的，这是可能的。

1）在表单上创建一个隐藏的div

2）在主窗体上创建一个指向ajax调用的链接。在您希望传输到您希望返回的Web服务器/数据服务器的链接上包含记录密钥信息。

3）在附加的.js文件中创建ajax调用和响应。在ajax调用查询中，将查找的密钥发送到服务器端响应php app。

4）在您的服务器端创建一个php响应应用程序

5）您的服务器端应用程序查找记录信息并通过简单的“echo”命令进行传回。

6）您的客户端应用程序将接收该信息。在ajax调用的响应部分中，将检索到的信息添加到隐藏状态并使其可见。

7）在弹出窗口中添加一个“关闭”链接以重新隐藏popUp。

我建议您通过JSON发送信息。这对于每个客户端和服务器来说非常简单，只需为每个客户端和服务器添加“编码”和“解码”行。

由于这是要显示的大量示例代码，如果您需要帮助的部分内容，只需针对您需要帮助的代码部分发布这些特定问题。

更改PHP注册表单响应对话框

1 个答案: