Question

我在通过父类列表显示子类属性时遇到问题。

的Xaml

<ListView Grid.Row="0" Grid.RowSpan="4" Grid.Column="0" x:Name="lvTest" ItemsSource="{Binding}" ScrollViewer.HorizontalScrollBarVisibility="Auto" SelectionMode="Single" ScrollViewer.VerticalScrollBarVisibility="Auto" Width="630" Height="270">
    <ListView.View>
        <GridView>
            <GridViewColumn Header="Index" DisplayMemberBinding="{Binding Path=index}" Width="100" />
            <GridViewColumn Header="Name" DisplayMemberBinding="{Binding Path=c.name}" Width="100" />
            <GridViewColumn Header="age" DisplayMemberBinding="{Binding Path=c.age}" Width="100" />
        </GridView>
    </ListView.View>
</ListView>

背后的代码

public partial class MainWindow : Window
{
    List<parent> parentList;

    public MainWindow()
    {
        InitializeComponent();

        GenerateList();

        lvTest.ItemsSource = parentList;
    }

    private void GenerateList()
    {
        parentList = new List<parent>();

        for (int i = 0; i < 10; i++)
        {
            parent p = new parent();
            p.index = i;

            child c = new child();
            c.name = "Name_" + (i + 1).ToString();
            c.age = i;

            parentList.Add(p);
        }
    }
}

类

public class parent
{
    public int index { get; set; }
    public child c { get; set; }
}

public class child
{
    public string name { get; set; }
    public int age { get; set; }
}

我无法显示子类的“name”和“age”属性，但访问时没有问题父类的索引属性。

任何人都知道怎么做？

Answer 1

您似乎忘记在child对象中“保存”parent个实例：

child c = new child();
c.name = "Name_" + (i + 1).ToString();
c.age = i;

p.c = c; // THIS!

数据绑定从父类列表中的ListView子类属性

1 个答案: