Question

这是我试图用来在一个表中显示来自多个MySQL表的信息的代码。如果表格信息不存在，我也会尝试创建一个else子句。这是我失败的尝试。

我一直在编辑它，因为我啄它，但此时我仍然无法在行不存在时显示最终的其他内容。

  <?
  include"db.inc.php";//database connection
  $item = "SELECT * FROM Item";
  $result = mysql_query($item);
  while ($row=mysql_fetch_array($result)) // Display information from Item Table.
  {
    echo ("<tr><td><a href=\"edit_item.php?id=$row[ItemID]\" target=\"_blank\">Edit</a></td>");
    echo ("<td>$row[ItemID]</td>");
    echo ("<td>$row[Category]</td>");
    echo ("<td>$row[Cost]</td>");
    echo ("<td>$row[Condition]</td>");
    echo ("<td>$row[PurchaseLot_PurchaseLotID]</td>");
    echo ("<td>$row[Location]</td>");
    echo ("<td>$row[Date]</td>");
    echo ("<td>$row[Desc]</td>");
    echo ("<td>$row[Notes]</td>");
    echo ("<td><a href=\"photo_upload.php?id=$row[ItemID]\" target=\"_blank\">Pics</a></td>");
    echo ("<td><a href=\"item_info.php?id=$row[ItemID]\" target=\"_blank\">Info</a></td></tr>");
    $info = "SELECT * FROM Info WHERE Item_ItemID = $row[ItemID] ";
    $info_results = mysql_query($info);
    while ($info_row = mysql_fetch_array($info_results))  
        {
        if ($info_row['Item_ItemID'] = $row['ItemID']) // Display Information from Info table If column exists with same ItemID.
            {
            echo ("<tr><td colspan=\"12\">");
            echo ("Manufacturer:$info_row[Manufacturer]<br>");
            echo ("Model:$info_row[Model]<br>");
            echo ("Model Number:$info_row[ModelNumber]<br>");
            echo ("Serial Number:$info_row[SerialNumber]<br>");
            echo ("Service Number:$info_row[ServiceNumber]<br>");
            echo ("</td></tr>");
            } else //else dispaly Add information to info link.
                    { 
                    echo ("<tr><td colspan=\"12\"><a href=\"item_info.php?id=$row[ItemID]\" target=\"_blank\">Add Extra Information</a></td></tr>");
                    }
        }
  }
  ?>

Answer 1

您可以将$ info "SELECT * FROM Info"中的SQL语句重新编写为"SELECT * FROM Info wHERE Item_ItemID=$row['ItemID'] ...然后删除

if ($info_row['Item_ItemID'] = $row['ItemID'])

再加上您的新代码after $info_results = mysql_query($info);

*已编辑*

然后你喜欢这个，而不是

while ($info_row = mysql_fetch_array($info_results))  
        {
        if ($info_row['Item_ItemID'] = $row['ItemID']) // Display Information from Info table If column exists with same ItemID.
            {
            echo ("<tr><td colspan=\"12\">");
            echo ("Manufacturer:$info_row[Manufacturer]<br>");
            echo ("Model:$info_row[Model]<br>");
            echo ("Model Number:$info_row[ModelNumber]<br>");
            echo ("Serial Number:$info_row[SerialNumber]<br>");
            echo ("Service Number:$info_row[ServiceNumber]<br>");
            echo ("</td></tr>");
            } else //else dispaly Add information to info link.
                    { 
                    echo ("<tr><td colspan=\"12\"><a href=\"item_info.php?id=$row[ItemID]\" target=\"_blank\">Add Extra Information</a></td></tr>");
                    }
        }

试试这个

if(mysql_num_rows($info)>0){ 
while($info_row = mysql_fetch_array($info){ 
echo ("<tr><td colspan=\"12\">");
            echo ("Manufacturer:$info_row[Manufacturer]<br>");
            echo ("Model:$info_row[Model]<br>");
            echo ("Model Number:$info_row[ModelNumber]<br>");
            echo ("Serial Number:$info_row[SerialNumber]<br>");
            echo ("Service Number:$info_row[ServiceNumber]<br>");
            echo ("</td></tr>");
} 
}else { 
echo ("<tr><td colspan=\"12\"><a href=\"item_info.php?id=$row[ItemID]\" target=\"_blank\">Add Extra Information</a></td></tr>"); 
}

Answer 2

我尝试编辑您的代码，但我无法尝试。

<?
  include"db.inc.php";//database connection
  $item = "SELECT * FROM Item";
  $result = mysql_query($item);
  while ($row=mysql_fetch_array($result)) // Display information from Item Table.
  {
    echo ("<tr><td><a href=\"edit_item.php?id=$row[ItemID]\" target=\"_blank\">Edit</a></td>");
    echo ("<td>$row[ItemID]</td>");
    echo ("<td>$row[Category]</td>");
    echo ("<td>$row[Cost]</td>");
    echo ("<td>$row[Condition]</td>");
    echo ("<td>$row[PurchaseLot_PurchaseLotID]</td>");
    echo ("<td>$row[Location]</td>");
    echo ("<td>$row[Date]</td>");
    echo ("<td>$row[Desc]</td>");
    echo ("<td>$row[Notes]</td>");
    echo ("<td><a href=\"photo_upload.php?id=$row[ItemID]\" target=\"_blank\">Pics</a></td>");
    echo ("<td><a href=\"item_info.php?id=$row[ItemID]\" target=\"_blank\">Info</a></td></tr>");
    $info = "SELECT * FROM Info where Item_ItemID = ".$row['ItemID'];
    $info_results = mysql_query($info);
    if ($info_row = mysql_fetch_array($info_results))  
        {
            echo ("<tr><td colspan=\"12\">");
            echo ("Manufacturer:$info_row[Manufacturer]<br>");
            echo ("Model:$info_row[Model]<br>");
            echo ("Model Number:$info_row[ModelNumber]<br>");
            echo ("Serial Number:$info_row[SerialNumber]<br>");
            echo ("Service Number:$info_row[ServiceNumber]<br>");
            echo ("</td></tr>");
        } 
        else { //else dispaly Add information to info link.
            echo ("<tr><td colspan=\"12\"><a href=\"item_info.php?id=$row[ItemID]\" target=\"_blank\">Add Extra Information</a></td></tr>");
         }        
  }
  ?>

我希望这就是答案。

使用PHP在一个HTML表中显示多个MySQL表，遇到循环问题

2 个答案: