Question

我有4个表，其中包含各种数据。

表1包含问题表2包含组表3包含选项表4包含具有“配置文件数据”列的作业应用程序

生成配置文件数据并将其转换为XML并存储在表4的profileData列中。其格式如下：

<proficiencies>
<question>
  <questionID>2</questionID>
  <questionGroup>2</questionGroup>
  <questionOptions>
     <option>19</option>
     <option>20</option>
     <option>31</option>
  </questionOptions>
</question>
<question>
  <questionID>1</questionID>
  <questionGroup>1</questionGroup>
  <questionOptions>
     <option>20</option>
     <option>29</option>
     <option>21</option>
  </questionOptions>
 </question>
 <question>
  <questionID>3</questionID>
  <questionGroup>2</questionGroup>
  <questionOptions>
     <option>18</option>
     <option>29</option>
  </questionOptions>
 </question>
</proficiencies>

现在，我正在创建一个页面，我需要使用所选的所有设置重新创建作业应用程序。当我创建XML时，我使用的是与实际问题和信息相关的ID号。

能够找出现在这些身份证号码的最佳方式是什么？我认为最好在存储过程中执行此操作，因为如果我在javascript中解析它时，它会有很多数据库调用。

不确定如何最好地解决这个问题或更改数据库的结构。

在这个例子中，我需要找出问题ID = 2等问题。

有更好的方法吗？

Answer 1

我认为您正在寻找XQuery。

下面的示例解析您的XML并加入问题表。它使用nodes()，query()和value()方法。

with MyXML
as
(
select
1 as MyXMLDataID
,cast('
<proficiencies>
<question>
  <questionID>2</questionID>
  <questionGroup>2</questionGroup>
  <questionOptions>
     <option>19</option>
     <option>20</option>
     <option>31</option>
  </questionOptions>
</question>
<question>
  <questionID>1</questionID>
  <questionGroup>1</questionGroup>
  <questionOptions>
     <option>20</option>
     <option>29</option>
     <option>21</option>
  </questionOptions>
 </question>
 <question>
  <questionID>3</questionID>
  <questionGroup>2</questionGroup>
  <questionOptions>
     <option>18</option>
     <option>29</option>
  </questionOptions>
 </question>
</proficiencies>' as xml) as MyXMLData),
MyQuestionGroups
as
(
select 1 as questionGroup, 'Education' as questionGroup_description
union
select 2 as questionGroup, 'Experience' as questionGroup_description
),
MyQuestions
as
(
select 1 as questionGroup, 1 as questionID, 'High school attendance' as question
union
select 2 as questionGroup, 2 as questionID, 'Alchemy experience' as question
union
select 2 as questionGroup, 3 as questionID, 'Arbitrage experience' as question
),
MyOptions
as
(
select 18 as optionID, '1 year' as option_description
union
select 19 as optionID, '2 year' as option_description
union
select 20 as optionID, '3 years' as option_description
union
select 21 as optionID, '4 year' as option_description
union
select 29 as optionID, '5 year' as option_description
union
select 31 as optionID, '6 years' as option_description
)
SELECT MyXML.MyXMLDataID
      ,t1.questionID.query('.') as questionID_node
      ,q.question
  FROM   MyXML
 CROSS APPLY MyXMLData.nodes('/proficiencies/question/questionID') as t1(questionID)
 INNER JOIN MyQuestions q 
         on q.questionID = t1.questionID.value('.', 'int')

返回此结果：

-----------------------------------------------
MyXMLDataID questionID_node question
-----------------------------------------------
1   <questionID>2</questionID>  Alchemy experience
1   <questionID>1</questionID>  High school attendance
1   <questionID>3</questionID>  Arbitrage experience

存储过程中的TSQL解析XML

1 个答案: