变量中的PHP标记和引号导致语法/解析错误

Question

这些行导致语法/解析错误，我不知道如何修复它。我很确定它是<?php和?>标签，还是单引号。有什么想法吗？

$data = '<?php
    $title = "'. $name. '";
    $keywords = "'. $title. ','. $developer. '";
    $description = "How to install '. $title. ' for PC and Mac.";

    include('templates/modheader.php');
    include('templates/modfooter.php');
    ?>';

提前致谢。

Answer 1

include('templates/modheader.php');
include('templates/modfooter.php');

是罪魁祸首：你混合单引号。完全使用

include("templates/modheader.php");
include("templates/modfooter.php");

Answer 2

include('templates/modheader.php');
include('templates/modfooter.php');

应该是

include("templates/modheader.php");
include("templates/modfooter.php");

Answer 3

对于大块字符串数据，我强烈推荐使用HEREDOC / NOWDOC语法。您可以将其与sprintf组合以注入值

$template = <<<'_PHP'
<?php
$title = '%s';
$keywords = $title . ',%s';
$description = "How to install $title for PC and Mac.";

include 'templates/modheader.php';
include 'templates/modfooter.php';
?>
_PHP;

$data = sprintf($template, $name, $developer);