Question

我尝试在c ++中捕获一个键入char *的字符串这是我的代码

void DBManager::printMatched(char* line, char* fileName)
{
    line = strtok(line,"Show");
    char* teamAName = strtok(line," ");
    char* teamACity = strtok(NULL,"-");
    char* teamBName = strtok(NULL," ");
    char* teamBCity = strtok(NULL,"\n");
}

这是正文中的文字 “显示abcde fghij - klmnop qrstu”

这是可变数据：

 teamAName = abcde
 teamACity = fghij
 teamBName = klmnop
 teamBCity = qrs

我如何修复teamBCity，我需要切入行中。

我在Linux系统上工作。

Answer 1

我认为这就是你想要的。鉴于你的例子，并不完全确定。它显然可以改进，也许你想使用更多的c ++ ish工具？

void DBManager::printMatched(char* line, char* fileName)
{
    char* linecpy   = strdup(line);

    char* dummy     = strtok(linecpy," ");
    char* teamAName = strtok(NULL," ");
    char* teamACity = strtok(NULL," ");
          dummy     = strtok(NULL," ");
    char* teamBName = strtok(NULL," ");
    char* teamBCity = strtok(NULL," \n");

    printf("teamAName %s\n", teamAName);
    printf("teamACity %s\n", teamACity);
    printf("teamBName %s\n", teamBName);
    printf("teamBCity %s\n", teamBCity);

    // do something with strings here?
}

c ++中的char *中的子字符串，strtok到行的末尾

1 个答案: