Question

这是我的查询。

select distinct m.number --as FirstAccount, m2.number as SecondAccount
from jm_people p
inner join master m on p.accountid = m.number
inner join JM_Subpoena s on m.number = s.number
inner join jm_people p2 on p.pid = p2.pid
inner join master m2 on p2.accountid = m2.number
inner join JM_Subpoena s2 on m2.number = s2.number
and m.number != m2.number

我需要比较s.dateRequested和s2.dateRequested，如果它们在6个月或之内，我需要返回结果。

关于如何做到这一点的任何想法？

例如：

s.dateRequested = '12/18/2013 00:00:000'
s2.dateRequested = '07/27/2013 00:00:000'

它将返回此结果，因为它们在6个月内

s.dateRequested = '12/18/2013 00:00:000'
s2.dateRequested = '03/27/2013 00:00:000'

它不会返回此结果。

Answer 1

使用DATEDIFF函数http://technet.microsoft.com/en-us/library/ms189794.aspx

select distinct m.number --as FirstAccount, m2.number as SecondAccount
from jm_people p
inner join master m on p.accountid = m.number
inner join JM_Subpoena s on m.number = s.number
inner join jm_people p2 on p.pid = p2.pid
inner join master m2 on p2.accountid = m2.number
inner join JM_Subpoena s2 on m2.number = s2.number
and m.number != m2.number
WHERE DATEDIFF( mm, s2.dateRequested, s.dateRequested) < 6 OR
DATEDIFF( mm, s2.dateRequested, s.dateRequested) = 6 
AND DATEPART( dd, s2.dateRequested) <= DATEPART( dd, s.dateRequested)

如果您需要6个月或更短的时间，您可以使用功能DATEPART（天数）和比较天数（6个月或同一天或更短时间）。

比较两个列日期返回，如果它们在6个月内

1 个答案: