Question

我试图将时间戳转换为人类可读的日期和时间。我试过了：

String dateSt = 1386580621268;
Log.i("*****", "date st is = "+dateSt);
long unixSeconds = Long.parseLong(dateSt);
Log.i("*******", "unix seconds is = "+unixSeconds);
Date date = new Date(unixSeconds*1000L); // *1000 is to convert seconds to milliseconds
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy"); // the format of your date
String formattedDate = sdf.format(date);
System.out.println(formattedDate);

预期结果为09-12-2013，但我得到28-12-45908。以上示例位于：Convert Unix timestamp to date java, answer by David Hofmann

Answer 1

试试这个，

public static String Epoch2DateString(long epochSeconds, String formatString) {
    Date updatedate = new Date(epochSeconds * 1000);
    SimpleDateFormat format = new SimpleDateFormat(formatString);
    return format.format(updatedate);
}

Answer 2

1386580621268不是unix时间戳，即自9-12-2013纪元以来的秒数，但是自纪元以来的毫秒数。删除*1000L或将输入除以1000。

Answer 3

我这样解决了。

public static String Epoch2DateString(String epochSeconds) {
    Date updatedate = new Date(Integer.parseInt(epochSeconds) * 1000L);
    SimpleDateFormat format = new SimpleDateFormat("dd-MM-yyyy");
    return format.format(updatedate);
}

将unix / epoch时间转换为格式化日期 - 意外日期

3 个答案: