我有阵列
Array
(
[0] => Array
(
[question_id] => 13
[is_break] => 0
)
[1] => Array
(
[question_id] => 14
[is_break] => 1
)
[2] => Array
(
[question_id] => 15
[is_break] => 0
)
[3] => Array
(
[question_id] => 16
[is_break] => 1
)
[4] => Array
(
[question_id] => 17
[is_break] => 1
)
)
如何按is_break = 1
拆分,所以我有question_id (13,14)(15,16)(17)
所以我有3个数组,数组[0]包含question_id 13和14数组[1]包含question_id 15和16,数组[2]包含question_id 17
答案 0 :(得分:2)
试试这个......
$count = 0;
$result = array();
foreach($array as $a) {
$result[$count][] = $a['question_id'];
if($a['is_break']) {
$count++;
}
}
请参阅 Codepad 。
答案 1 :(得分:1)
做这样的事情.. [ FYI :这适用于PHP> = 5.5 ]
$new_array = array_chunk(array_column($your_array,'question_id'),2);
var_dump($new_array);
答案 2 :(得分:1)
$questions = array();
foreach ($main_array as $subarray) {
if($subarray['is_break'] == 1) {
array_push($questions, $subarray['question_id']);
}
}
现在$questions
数组有问题ID。